hyp*_*erN 5 .net entity-framework database-migration ef-code-first ef-migrations
当我尝试做Update-Database时,我收到此错误:
导航属性"SenderId"不是"对话"类型的声明属性.验证它是否未从模型中明确排除,并且它是有效的导航属性.
编辑
我认为问题在于对话和用户之间的映射关系,因为对话和用户与两个一对多关系连接,即对话有两个指向用户的外键
以下是用户和对话的连接方式:
用户:
public class User
{
[Key]
[HiddenInput(DisplayValue = false)]
[DatabaseGenerated(DatabaseGeneratedOption.Identity)]
public Guid UserId { get; set; }
public virtual ICollection<Conversation> ConversationSenders { get; set; }
public virtual ICollection<Conversation> ConversationRecievers { get; set; }
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会话:
public class Conversation
{
[Key]
[HiddenInput(DisplayValue = false)]
public Guid ConversationId { get; set; }
[ForeignKey("SenderId")]
public Guid SenderId { get; set; }
[ForeignKey("RecieverId")]
public Guid RecieverId { get; set; }
[InverseProperty("ConversationSenders")]
public virtual User Sender { get; set; }
[InverseProperty("ConversationRecievers")]
public virtual User Reciever { get; set; }
}
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这是完整的代码:
用户:
public class User
{
[Key]
[HiddenInput(DisplayValue = false)]
[DatabaseGenerated(DatabaseGeneratedOption.Identity)]
public Guid UserId { get; set; }
[DatabaseGenerated(DatabaseGeneratedOption.Identity)]
public Guid CollegeId { get; set; }
public int RoleId { get; set; }
[Required]
[DataType(DataType.EmailAddress)]
public string Email { get; set; }
[Required]
[DataType(DataType.Password)]
public string Password { get; set; }
[Required]
public string Name { get; set; }
[Required]
public string Surname { get; set; }
public string Gender { get; set; }
//role
public DateTime? DateOfBirth { get; set; }
public string ImageURL { get; set; }
[ForeignKey("CollegeId")]
public virtual College College { get; set; }
[ForeignKey("RoleId")]
public virtual UserRole UserRole { get; set; }
public virtual ICollection<Advert> Adverts { get; set; }
public virtual ICollection<Competition> Competitions { get; set; }
public virtual ICollection<Message> Messages { get; set; }
public virtual ICollection<Conversation> ConversationSenders { get; set; }
public virtual ICollection<Conversation> ConversationRecievers { get; set; }
public virtual ICollection<UserOS> UserOses { get; set; }
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会话:
public class Conversation
{
[Key]
[HiddenInput(DisplayValue = false)]
[DatabaseGenerated(DatabaseGeneratedOption.Identity)]
public Guid ConversationId { get; set; }
[ForeignKey("SenderId")]
[DatabaseGenerated(DatabaseGeneratedOption.Identity)]
public Guid SenderId { get; set; }
[ForeignKey("RecieverId")]
[DatabaseGenerated(DatabaseGeneratedOption.Identity)]
public Guid RecieverId { get; set; }
[InverseProperty("ConversationSenders")]
public virtual User Sender { get; set; }
[InverseProperty("ConversationRecievers")]
public virtual User Reciever { get; set; }
public virtual ICollection<Message> Messages { get; set; }
}
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信息
public class Message
{
[Key]
[HiddenInput(DisplayValue = false)]
[DatabaseGenerated(DatabaseGeneratedOption.Identity)]
public Guid MessageId { get; set; }
[HiddenInput(DisplayValue = false)]
public Guid UserId { get; set; }
[HiddenInput(DisplayValue = false)]
public Guid ConversationId { get; set; }
public string Text { get; set; }
public bool? IsSeen { get; set; }
[ForeignKey("UserId")]
public virtual User ConversationSender { get; set; }
[ForeignKey("ConversationId")]
public virtual Conversation Conversation { get; set; }
}
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最后我找到了解决方案,愚蠢的错误.在保护中它应该是
[ForeignKey("Sender"), Column(Order = 0)]
public Guid SenderId { get; set; }
[ForeignKey("Receiver"), Column(Order = 1)]
public Guid ReceiverId { get; set; }
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并不是
[ForeignKey("SenderId"), Column(Order = 0)]
[ForeignKey("ReceiverId"), Column(Order = 1)]
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之后我得到了错误:
"在表'对话'上引入FOREIGN KEY约束'FK_dbo.Conversations_dbo.Users_ReceiverId'可能会导致循环或多个级联路径.指定ON DELETE NO ACTION或ON UPDATE NO ACTION,或修改其他FOREIGN KEY约束.无法创建约束.请参阅上一页错误".
解决方案是:在DbContext中这段代码:
modelBuilder.Entity<Conversation>()
.HasRequired(s => s.Sender)
.WithMany(s => s.ConversationSenders)
.HasForeignKey(s => s.SenderId)
.WillCascadeOnDelete(false);
modelBuilder.Entity<Conversation>()
.HasRequired(r => r.Receiver)
.WithMany(r => r.ConversationReceivers)
.HasForeignKey(r => r.ReceiverId)
.WillCascadeOnDelete(false);
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我已经测试过,现在一切正常=)
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