bod*_*sam 11 php xml api curl header
我想通过API向Web服务发送请求,如下所示,我必须传递自定义http标头(Hash),我使用CURL,我的代码似乎工作但我没有得到严格的响应,我被告知它与哈希值有关,虽然值被认为是正确的,我传递它或代码本身的方式有什么不对.
<?php
$ttime=time();
$hash="123"."$ttime"."dfryhmn";
$hash=hash("sha512","$hash");
$curl = curl_init();
curl_setopt($curl,CURLOPT_HTTPHEADER,array('Hash:$hash'));
curl_setopt ($curl, CURLOPT_URL, 'http://web-service-api.com/getresult.xml?clientid=456&time=$ttime');
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$xml = curl_exec ($curl);
if ($xml === false) {
die('Error fetching data: ' . curl_error($curl));
}
curl_close ($xml);
echo htmlspecialchars("$xml", ENT_QUOTES);
?>
Run Code Online (Sandbox Code Playgroud)
Raf*_*shi 14
如果您需要在php中获取并设置自定义http标头,以下简短教程非常有用:
发送请求标头
$uri = 'http://localhost/http.php';
$ch = curl_init($uri);
curl_setopt_array($ch, array(
CURLOPT_HTTPHEADER => array('X-User: admin', 'X-Authorization: 123456'),
CURLOPT_RETURNTRANSFER =>true,
CURLOPT_VERBOSE => 1
));
$out = curl_exec($ch);
curl_close($ch);
// echo response output
echo $out;
Run Code Online (Sandbox Code Playgroud)
阅读自定义标题
print_r(apache_request_headers());
Run Code Online (Sandbox Code Playgroud)
你应该看到
Array
(
[Host] => localhost
[Accept] => */*
[X-User] => admin
[X-Authorization] => 123456
[Content-Length] => 9
[Content-Type] => application/x-www-form-urlencoded
)
Run Code Online (Sandbox Code Playgroud)
使用PHP CGI自定义标头
在.htaccess
RewriteEngine On
RewriteRule .? - [E=User:%{HTTP:X-User}, E=Authorization:%{HTTP:X-Authorization}]
Run Code Online (Sandbox Code Playgroud)
从$ _SERVER中读取自定义标头
echo $_SERVER['User'];
echo $_SERVER['Authorization'];
Run Code Online (Sandbox Code Playgroud)
资源