set*_*eth 15
这是一种方式:
function loadDaFun() {
var script = document.createElement('script');
script.src = '/path/to/your/script.js';
var head = document.getElementsByTagName("head")[0];
head.appendChild(script);
}
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CMS*_*CMS 12
该@seth的答案是完全正确的,但你并不需要离开插入的script
元素上的DOM,你可以删除它,它加载刚过,也是你可能想知道,当插入脚本就可以使用,例如你可以:
function loadScript(url, completeCallback) {
var script = document.createElement('script'), done = false,
head = document.getElementsByTagName("head")[0];
script.src = url;
script.onload = script.onreadystatechange = function(){
if ( !done && (!this.readyState ||
this.readyState == "loaded" || this.readyState == "complete") ) {
done = true;
completeCallback();
// IE memory leak
script.onload = script.onreadystatechange = null;
head.removeChild( script );
}
};
head.appendChild(script);
}
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用法:
loadScript("http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js",
function () { alert('jQuery has been loaded.'); });
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