如何在python中快速禁用try语句进行测试？

Question

说我有以下代码:

try:
    print 'foo'
    # A lot more code...
    print 'bar'
except:
    pass

我如何进行测试以禁用try-statement临时？

你不能只评论try和except排除因为缩进仍然是关闭的.

有没有比这更简单的方法？

#try:
print 'foo'
# A lot more code...
print 'bar'
#except:
#    pass

Answer 1

您可以将异常作为except块的第一行重新加载,它的行为与没有try/except的情况一样.

try:
    print 'foo'
    # A lot more code...
    print 'bar'
except:
    raise # was: pass

Answer 2

从velotron的回答中贪图,我喜欢这样做的想法:

try:
    print 'foo'
    # A lot more code...
    print 'bar'
except:
    if settings.DEBUG:  # Use some boolean to represent dev state, such as DEBUG in Django
        raise           # Raise the error
    # Otherwise, handle and move on. 
    # Typically I want to log it rather than just pass.
    logger.exception("Something went wrong")

Answer 3

把它变成一个if True语句,except由else分支"注释掉"子句(永远不会被执行):

if True: # try:
    # try suite statements
else: # except:
    # except suite statements

这else:是可选的,你也可以注释掉整个except:套件,但是通过使用else:你可以让整个except:套件缩进和取消注释.

所以:

try:
    print 'foo'
    # A lot more code...
    print 'bar'
except SomeException as se:
    print 'Uhoh, got SomeException:', se.args[0]

变为:

if True: # try:
    print 'foo'
    # A lot more code...
    print 'bar'
else: # except SomeException as se:
    print 'Uhoh, got SomeException:', se.args[0]

Answer 4

让你except唯一能捕获到的东西是try方块不会抛出的：

class FakeError:
    pass

try:
    # code
except FakeError: # OldError:
    # catch

实际上不确定这是否是一个好主意，但它确实有效！