Scala构造函数继承

Question

这是一件事:我有一些基本类,例如:

abstract class Car(private val model: String = "no name")

我希望课程扩展Car, for example:

class Mazda(model: String) extends Car(model)

My question is: how to create Mazda instance without given model like that: new Mazda,例如:

abstract class Car(private val model: String = "no name")

我的问题是:如何在没有给定模型的情况下创建Mazda实例:no name并且具有名称的对象Car, for example:

class Mazda(model: String) extends Car(model)

My question is: how to create Mazda instance without given model like that: new Mazda？

Answer 1

要实现您的目标,您必须在子类中定义默认值:

class Mazda(model: String = "no name") extends Car(model)