django/ajax:无法在views.py中获取Ajax发布数据

Question

我从django后端获取ajax发布数据时遇到问题,我不知道如何传递该值,请帮忙.

在HTML中我只是这个:

<form id="get_vulns_from_family">
    <label for="family_content">Enter a family name to display the NVTs</label>
    <input id="family_content" />
    <input type="submit" value="search" />
</form>

在javascript中我写了这个:

$(function() {
    $("#get_vulns_from_family").submit(function(event) {
        var family_text = $("#family_content").val();
        var family_data = {"family": family_text};
        $.ajax({
            url: "/template_conf/get_vulns_from_family",
            type: "POST",
            data: family_data,
            success: function(response) {
                console.log(response);
            },
            error: function(response) {
                console.log("failed!");
            }
        });
        // prevent default posting of form
        event.preventDefault();
    });
});

在与url对应的Django方法中/template_conf/get_vulns_from_family,我试过这个:

def get_vuln_from_family(request):
    family = request.POST['family']
    # some other operations to get value for variable "json_data"
    return HttpResponse(simplejson.dumps(json_data))

但是django说:MultiValueDictKeyError: "Key 'family' not found in <QueryDict: {}>"这意味着POST字典是空的.我使用错误的方式获取发布数据吗？如果是这样我该怎么办？谢谢.

Answer 1

你的网址"/template_conf/get_vulns_from_family"缺少一个斜杠.django通常会将此重定向到"/template_conf/get_vulns_from_family/"丢弃POST数据