为什么不编译？不匹配'operator&='

Question

我尝试编译时遇到一个奇怪的错误:

class CucumberMarket {
public:
  bool ans;
  int n,cont,K,b;
  bool check(const vector<int> &precios,long long price,int pos) {
    ++cont;
    if(cont == K and b < price) ans = false;
    if(!ans) return ans;
    for(int i = pos + 1; i < n; ++i) {
      if(cont < K) ans &= check(precios,price + precios[i],i);
    }
    --cont;
  }
  string check(vector <int> price, int budget, int k) {
    n = price.size();
    K = k;
    b = budget;
    ans = true;
    cont = 0;
    for(int i = 0; i < n and ans; ++i) ans &= (this -> check(price,price[i],i));
    return ans ? "YES" : "NO";
  }
};

这就是我得到的:

C:\Users\Usuario\Desktop\Temp\C++\tc.cpp: In member function `std::string CucumberMarket::check(std::vector<int, std::allocator<int> >, int, int)':
C:\Users\Usuario\Desktop\Temp\C++\tc.cpp:24: error: no match for 'operator&=' in '((CucumberMarket*)this)->CucumberMarket::ans &= CucumberMarket::check(std::vector<int, std::allocator<int> >, int, int)(vector<int,std::allocator<int> >(((const std::vector<int, std::allocator<int> >&)((const std::vector<int, std::allocator<int> >*)(&price)))), (&price)->std::vector<_Tp, _Alloc>::operator[] [with _Tp = int, _Alloc = std::allocator<int>](((unsigned int)i)), i)'
[Finished in 0.2s with exit code 1]

第24行是这样的:

for(int i = 0; i < n and ans; ++i) ans &= (this -> check(price,price[i],i));

我不明白,为什么我得到这个？我以前做过这个,它总是被编译

Answer 1

std::string CucumberMarket::check似乎是在检查返回的假设下string.这是你的问题,你应该采取bool回归的问题.
如果你想让它正常工作,最简单的解决方法就是强制price[i]转换long long为如下所示

for(int i = 0; i < n and ans; ++i) ans &= (this -> check(price,(long long)price[i],i));

我会建议你的重载不要太接近签名明智.