用于从美国城市名称获取经度和纬度的Python模块?

Dee*_*k B 11 python geolocation

我正在寻找一个python模块,它可以将城市名称作为输入,并返回输入的纬度和经度.

eum*_*iro 27

看看geopy.在"入门"文档中,它显示:

>>> from geopy import geocoders  
>>> gn = geocoders.GeoNames()

>>> print gn.geocode("Cleveland, OH 44106")
(u'Cleveland, OH, US', (41.4994954, -81.6954088))

>>> gn.geocode("Cleveland, OH", exactly_one=False)[0]
(u'Cleveland, OH, US', (41.4994954, -81.6954088))
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  • 我必须在http://www.geonames.org/login中创建一个帐户,为我的帐户启用免费的Web服务并发出`gn = geocoders.GeoNames(username ='account_username')` (10认同)
  • 编辑:找到了。这有点违反直觉,它是登录名和密码框下方的链接(看起来好像您需要登录,但实际上它发生在外部) (2认同)

jmu*_*sch 13

一个例子:

from geopy.geocoders import Nominatim
geolocator = Nominatim(user_agent='myapplication')
location = geolocator.geocode("Chicago Illinois")
print(location.address)
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可用信息:

>>> location.raw
{u'display_name': u'Chicago, Cook County, Illinois, United States of America', u
'importance': 1.0026476104889, u'place_id': u'97957568', u'lon': u'-87.6243706',
 u'lat': u'41.8756208', u'osm_type': u'relation', u'licence': u'Data \xa9 OpenSt
reetMap contributors, ODbL 1.0. http://www.openstreetmap.org/copyright', u'osm_i
d': u'122604', u'boundingbox': [u'41.6439170837402', u'42.0230255126953', u'-87.
9401016235352', u'-87.5239791870117'], u'type': u'city', u'class': u'place', u'i
con': u'http://nominatim.openstreetmap.org/images/mapicons/poi_place_city.p.20.p
ng'}
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  • 2022 年仍然有效,无需 API 密钥。 (3认同)