如何覆盖List <T>包含

Question

我想使用List [MyObject]比较属性而不是整个对象.因此我使用IEquatable [MyObject],但编译器仍然需要MyObject而不是string属性.为什么？

这是我得到的:

public class AnyClass
{
    public List<AnyOtherClass> MyProperty { get; set; }        
    public string AnyProperty { get; set; }

    public AnyClass(string[] Names, string[] Values, string AnyProperty)
    {
        this.AnyProperty = AnyProperty;
        this.MyProperty = new List<AnyOtherClass>();
        for (int i = 0; i < Names.Length; i++)
            MyProperty.Add(new AnyOtherClass(Names[i], Values[i]));
    }
}

public class AnyOtherClass : IEquatable<string>
{
    public AnyOtherClass(string Name, string Values)
    {
        this.Name = Name;
        this.Values = Values.Split(';').ToList();
    }

    public string Name { get; set; }
    public List<string> Values { get; set; }

    public bool Equals(string other)
    {
        return this.Name.Equals(other);
    }
}

    private void DoSomething()
    {
        string[] Names = new string[] { "Name1", "Name2" };
        string[] Values = new string[] { "Value1_1;Value1_2", "Value2" };
        AnyClass ac = new AnyClass(Names, Values, "any Property");

        if (ac.MyProperty.Contains("Name1")) //Problem is here...
            //do something
    }

Answer 1

您可能想尝试使用此:

myList.Any(x => x.someProperty == someValue);

来自MSDN:http://msdn.microsoft.com/en-us/library/bb534972.aspx

确定序列的任何元素是否满足条件.

如果您不知道,x => x.someProperty == someValue则称为a lambda expression.

请注意,您可以在任何实现中使用它IEnumerable,这样就不会限制您List<T>.