如何从移动浏览器启动应用程序(facebook/twitter/etc),但如果未安装应用程序,则回退到超链接

Question

我希望可能有某种方法可以检测uri:scheme是否在浏览器中的移动设备上注册.

IE:我想检查是否安装了facebook,twitter,pinterest应用程序,并且可以从他们相关的uri:scheme启动.

if(fb_isInstalled) {
    // href="fb://profile/...."
} else {
    // href="http://m.facebook.com/..."
}

基本上,如果用户已安装了facebook,则启动应用程序,但如果未安装该应用程序,则会回退到fb网站的移动版本.

Answer 1

我想我有一个有效的解决方案.

 <!-- links will work as expected where javascript is disabled-->
 <a class="intent"   
    href="http://facebook.com/someProfile"   
    data-scheme="fb://profile/10000">facebook</a>

我的javascript就是这样的.
注意:那里有一个混合的jQuery,但如果你不想,你不需要使用它.

(function () {

    // tries to execute the uri:scheme
    function goToUri(uri, href) {
        var start, end, elapsed;

        // start a timer
        start = new Date().getTime();

        // attempt to redirect to the uri:scheme
        // the lovely thing about javascript is that it's single threadded.
        // if this WORKS, it'll stutter for a split second, causing the timer to be off
        document.location = uri;

        // end timer
        end = new Date().getTime();

        elapsed = (end - start);

        // if there's no elapsed time, then the scheme didn't fire, and we head to the url.
        if (elapsed < 1) {
            document.location = href;
        }
    }

    $('a.intent').on('click', function (event) {
        goToUri($(this).data('scheme'), $(this).attr('href'));
        event.preventDefault();
    });
})();

我也把它当作一个你可以分叉和捣乱的要点.如果您愿意,您还可以在jsfiddle中包含要点.

编辑

@kmallea分享了要点并从根本上简化了它. https://gist.github.com/kmallea/6784568

// tries to execute the uri:scheme
function uriSchemeWithHyperlinkFallback(uri, href) {
    if(!window.open(uri)){
        window.location = href;
    }
}

// `intent` is the class we're using to wire this up. Use whatever you like.
$('a.intent').on('click', function (event) {
    uriSchemeWithHyperlinkFallback($(this).data('scheme'), $(this).attr('href'));
    // we don't want the default browser behavior kicking in and screwing everything up.
    event.preventDefault();
});