java调用main方法数组参数(容易但令人困惑)

Ben*_*Jun 3 java recursion

我想在main方法中调用代码,但它似乎并没有真正起作用.

public class RecursiveSelectionSort {

public static void sort(double [] list){


    sort(list, 0, list.length -1);
}
public static void sort(double [] list, int low, int high){
    if (low < high){
        int indexOfMin = low;
        double min = list[low];
        for(int i = low + 1; i <= high; i++){
            if(list[i]< min){
                min = list[i];
                indexOfMin = i;
            }
        }
        list[indexOfMin] = list[low];
        list[low] = min;

        sort(list, low + 1, high);
    }
}
public static void main(String [] args){
    double [] list = {3.0,4.0,1.0};//I tried but it doesn't work
    System.out.print(sort(list));//it doesn't go to sort(list);
}
}
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我想知道我是否可以打电话给它.这似乎很容易,但真的令人困惑.

Pau*_*ora 5

该方法sort返回void,但您尝试将其结果传递给print.试试这个:

double [] list = {3.0,4.0,1.0};
sort(list);
System.out.print(Arrays.toString(list));
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注意我也使用了实用方法Arrays.toString,这是必要的,因为数组本身不会覆盖toString以显示其内容.