导出mongoose数据库模块

Question

我需要导出我的mongoose数据库模块,所以我可以使用我程序中每个模块的定义模型.

例如,我的database.js模块看起来像这样:

var mongoose = require('mongoose'),
    db = mongoose.createConnection('mongodb://localhost/newdb'),
    Schema = mongoose.Schema;

db.on('error', console.error.bind(console, 'connection error:'));
db.once('open', function callback () {
    console.log("Connected to database newdb");

    var dynamicUserItemSchema = new mongoose.Schema({
      userID: Number,
      rank:  Number,
    });

    var staticUserItemSchema = new mongoose.Schema({
        _id: Schema.Types.Mixed,
        type: Schema.Types.Mixed,
    });

    var DynamicUserItem = db.model('DynamicUserItem', dynamicUserItemSchema);
    var StaticUserItem = db.model('StaticUserItem', staticUserItemSchema);

});

我想能够添加var db = require('../my_modules/database');到我的程序的任何其他模块 - 所以我将能够使用这样的模型:

db.DynamicUserItem.find(); 要么 item = new db.DynamicUserItem({});

是否可以使用"出口"或"模块出口"来做到这一点？谢谢.

Answer 1

我通常不使用error和open事件,并按照mongoosejs中的示例创建与我的数据库的连接.使用该示例,您可以执行以下操作.

db.js

var mongoose = require('mongoose');
var db = mongoose.createConnection('localhost', 'test');

var schema = mongoose.Schema({ name: 'string' });
var Cat = db.model('Cat', schema);

module.exports = Cat; // this is what you want

然后在你的app.js中你可以做类似的事情

var Cat = require('db');

var peter = new Cat();

希望有所帮助!

Answer 2

您可以使用导出来定义其他地方可能需要的模块:

./models/list.js

var ListSchema = new Schema({
    name                : { type: String, required: true, trim: true }
    , description   : { type: String, trim: true }
});

module.exports = db.model('List', ListSchema);

./routes/list.js

var list = module.exports = {};

var List = require('../models/list');

list.get = function(req, res){
        List.find({ user: user._id }).exec(function(err, lists){
            res.render('lists', {
                lists: lists,
            });
        });
    });
};

./app.js

app.get('lists', routes.lists.get);