如何使用$ location服务对angularjs控制器进行单元测试

Question

我正在尝试创建一个简单的单元测试来测试我的show函数.

我收到以下错误:

TypeError: Object #<Object> has no method 'show'

好像$rootScope不是控制器的范围？

这是我的控制器:

function OpponentsCtrl($scope, $location) {
    $scope.show = function(url) {
        $location.path(url);
    }
}
OpponentsCtrl.$inject = ['$scope', '$location'];

这是我的控制器单元测试:

describe('OpponentsCtrl', function() {
    beforeEach(module(function($provide) {
        $provide.factory('OpponentsCtrl', function($location){
            // whatever it does...
        });
    }));

    it('should change location when setting it via show function', inject(function($location, $rootScope, OpponentsCtrl) {
        $location.path('/new/path');
        $rootScope.$apply();
        expect($location.path()).toBe('/new/path');

        $rootScope.show('/test');
        expect($location.path()).toBe('/test');
    }));
});

Answer 1

这就是我的测试最终工作的方式.

describe('OpponentsCtrl', function() {
    var scope, rootScope, ctrl, location;

    beforeEach(inject(function($location, $rootScope, $controller) {
        location = $location;
        rootScope = $rootScope;
        scope = $rootScope.$new();
        ctrl = $controller(OpponentsCtrl, {$scope: scope});
    }));

    it('should change location when setting it via show function', function() {
        location.path('/new/path');
        rootScope.$apply();
        expect(location.path()).toBe('/new/path');

        // test whatever the service should do...
        scope.show('/test');
        expect(location.path()).toBe('/test');

    });
});

Answer 2

为什么不简单地使用spyOn函数？

describe('OpponentsCtrl', function() {

    var location;

    beforeEach(module(function($provide) {
        $provide.factory('OpponentsCtrl', function($location){
            location = $location;
        });
    }));

    it('should change location when setting it via show function', inject(function() {    
        spyOn(location, 'path');    
        expect(location.path).toHaveBeenCalledWith('/new/path');
    }));
});

希望这可以帮助!