XSLT是否具有Split()函数？

Question

我在节点中有一个字符串,我想将字符串拆分为'？' 并返回数组中的最后一项.

例如,在下面的块中:

<a>
    <xsl:attribute name="href">
        /newpage.aspx?<xsl:value-of select="someNode"/>
    </xsl:attribute>
    Link text
</a>

我想分割someNode价值.

编辑:这是我用来为我的Asp.Net页面加载Xsl的VB.Net:

Dim xslDocPath As String = HttpContext.Current.Server.MapPath("~/App_Data/someXslt.xsl")
Dim myXsltSettings As New XsltSettings()
Dim myXMLResolver As New XmlUrlResolver()

myXsltSettings.EnableScript = True
myXsltSettings.EnableDocumentFunction = True

myXslDoc = New XslCompiledTransform(False)
myXslDoc.Load(xslDocPath, myXsltSettings, myXMLResolver)

Dim myStringBuilder As New StringBuilder()
Dim myXmlWriter As XmlWriter = Nothing

Dim myXmlWriterSettings As New XmlWriterSettings()
myXmlWriterSettings.ConformanceLevel = ConformanceLevel.Auto
myXmlWriterSettings.Indent = True
myXmlWriterSettings.OmitXmlDeclaration = True

myXmlWriter = XmlWriter.Create(myStringBuilder, myXmlWriterSettings)

myXslDoc.Transform(xmlDoc, argumentList, myXmlWriter)

Return myStringBuilder.ToString()

更新:这是在特定节点上拆分XML的示例

Answer 1

使用递归方法:

<xsl:template name="output-tokens">
    <xsl:param name="list" /> 
    <xsl:variable name="newlist" select="concat(normalize-space($list), ' ')" /> 
    <xsl:variable name="first" select="substring-before($newlist, ' ')" /> 
    <xsl:variable name="remaining" select="substring-after($newlist, ' ')" /> 
    <id>
        <xsl:value-of select="$first" /> 
    </id>
    <xsl:if test="$remaining">
        <xsl:call-template name="output-tokens">
            <xsl:with-param name="list" select="$remaining" /> 
        </xsl:call-template>
    </xsl:if>
</xsl:template>

Answer 2

如果您可以使用XSLT 2.0或更高版本,则可以使用tokenize(string, separator):

tokenize("XPath is fun", "\s+")
Result: ("XPath", "is", "fun")

请参阅w3schools XPath函数参考.

默认情况下,.NET不支持XSLT 2.0,更不用说XSLT 3.0了..NET的唯一已知2.0+处理器是Saxon for .NET带有IKVM的,Exselt,目前处于测试阶段的.NET XSLT 3.0处理器以及XMLPrime XSLT 2.0处理器.

Answer 3

我最终使用了这个substring-after()功能.这对我有用:

<a>
    <xsl:attribute name="href">
        /newpage.aspx?<xsl:value-of select="substring-after(someNode, '?')"/>
    </xsl:attribute>
    Link text
</a>

即使将我的XSLT版本设置为2.0,我仍然'tokenize()' is an unknown XSLT function.在尝试使用时出现" "错误tokenize().

Answer 4

添加另一种可能性,如果您的模板引擎支持EXSLT,那么您可以使用tokenize().

例如:

<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns:str="http://exslt.org/strings"
                extension-element-prefixes="str">

...
  <a>
    <xsl:attribute name="href">
      <xsl:text>/newpage.aspx?</xsl:text>
      <xsl:value-of select="str:tokenize(someNode)[2]"/>
    </xsl:attribute>              
  </a>
...
</xsl:stylesheet>