mst*_*and 6 .net c# linq lambda linq-to-objects
我需要帮助创建一个lambda表达式来查询以下列表,以便检索每个通道中价格最低的项目.即,对于该示例项目A,D和G.
class Radio
{
public string Name { get; set; }
public int Channel { get; set; }
public decimal Price { get; set; }
}
List<Radio> radios = new List<Radio>();
radios.Add(new Radio() { Name = "A", Channel = 1, Price = 10 });
radios.Add(new Radio() { Name = "B", Channel = 1, Price = 20 });
radios.Add(new Radio() { Name = "C", Channel = 1, Price = 30 });
radios.Add(new Radio() { Name = "D", Channel = 2, Price = 10 });
radios.Add(new Radio() { Name = "E", Channel = 2, Price = 20 });
radios.Add(new Radio() { Name = "F", Channel = 2, Price = 30 });
radios.Add(new Radio() { Name = "G", Channel = 3, Price = 10 });
radios.Add(new Radio() { Name = "H", Channel = 3, Price = 20 });
radios.Add(new Radio() { Name = "I", Channel = 3, Price = 30 });
Run Code Online (Sandbox Code Playgroud)
Til*_*lak 15
使用Linq,
第一组使用Enumerable.GroupBy
然后排序使用Enumerable.OrderBy
然后采取首先在组中的每个分类项
radios.GroupBy(x=> x.Channel).Select(x=>x.OrderBy(y=>y.Price)).Select(x=>x.First());
Run Code Online (Sandbox Code Playgroud)
Raw*_*ing 12
您也可以在不对每个组进行昂贵的排序的情况下执行此操作:
radios.GroupBy(x => x.Channel).Select(g =>
g.Aggregate((r1, r2) => r1.Price < r2.Price ? r1 : r2));
Run Code Online (Sandbox Code Playgroud)
在Aggregate通过各组一次迭代,跟踪到目前为止,它的发现最便宜的无线和替换它,如果它找到一个便宜的.