字符串比较w/if语句

Question

我试图将EditText字段中的字符串与共享首选项中的字符串进行比较.如果字符串匹配,则启动新活动.Sharedpreferenced中的字符串使用Base64编码.我试图将编辑文本字符串与sharedpreferences字符串进行比较后解码但无法正确编码.我怎样才能正确编码.例子表示赞赏.我的比较器在第77和78行

 44. public void onClick(View arg0) {
 45.    
 46.   sp=this.getSharedPreferences("AccessApp", MODE_WORLD_READABLE);
 47.  
 48.   
 49.   
 50.   
 51.   byte[] key = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 3, 4, 5 };
 52.   
 53.   
 54.   try {
 55.    user = sp.getString("USERNAME_KEY", null);
 56.        String decryptedUser = decrypt(user, key);  
 57.        
 58.         
 59.   }
 60.  catch (Exception e) {
 61.   // TODO Auto-generated catch block
 62.   e.printStackTrace();
 63.  }   
 64.  try {
 65.       pass = sp.getString("PASSWORD_KEY", null);
 66.       String decryptedPass = decrypt(pass, key);  
 67.       
 68.        
 69.
 70. } catch (Exception e) {
 71.   // TODO Auto-generated catch block
 72.   e.printStackTrace();
 73. }
 74.  
 75.  if(lBttn.equals(arg0)){
 76.    
 77.     if((uname.getText().toString().equals(decryptedUser))  && 
 78.       (pword.getText().toString().equals(decryptedPass)))
 79.      
 80.           {
 81.         Toast.makeText(this, "You are Logged In", 20000).show();
 82.                
 83.              Intent intent;
 84.               intent=new Intent(this,details.class);
 85.               startActivity(intent);
 86.             flag=1;
 87.           }

Answer 1

有2份decryptedUser 和decryptedPass每个.try块中有一对,另一对是成员.它们在第77行始终为空,因为您将解密的值分配给您从不使用的不同变量(第56和66行).将整个代码移动到一个try块中.

public void onClick(View arg0) {
    ...
    ...
    String decryptedUser;
    String decryptedPass;
    try {
        user = sp.getString("USERNAME_KEY", null);
        decryptedUser = decrypt(user, key);  
        pass = sp.getString("PASSWORD_KEY", null);
        decryptedPass = decrypt(pass, key);
        /* Your if statements follow from here */
        ...
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }   

}