HAVING COUNT(DISTINCT `goodfor_what`.`name`) = 3 导致错误消息

Question

我收到错误消息

您的 SQL 语法有错误；检查与您的 MySQL 服务器版本相对应的手册，了解在 GROUP BY name HAVING COUNT(DISTINCT goodfor_when.name) = 1 附近使用的正确语法。

这是发生错误的查询的一部分

                    ....
        WHERE 
        ( `city`.`name` = "London" ) AND 
        `goodfor_what`.`name` IN ("Beers","Wine","Food") 
        GROUP BY name 

        HAVING COUNT(DISTINCT `goodfor_what`.`name`) = 3 AND `goodfor_when`.`name` IN ('Daytime') GROUP BY name
        HAVING COUNT(DISTINCT `goodfor_when`.`name`) = 1 ORDER BY `t`.`name`, `t`.`id`;

但如果删除线就可以了

HAVING COUNT(DISTINCT `goodfor_what`.`name`) = 3 AND `goodfor_when`.`name` IN ('Daytime') GROUP BY name

Answer 1

同一查询中不能有两个HAVING或两个命令，并且必须放在. 所以，例如：GROUP BYGROUP BYHAVING

GROUP BY name
HAVING (COUNT(DISTINCT `goodfor_what`.`name`) = 3 AND `goodfor_when`.`name` IN ('Daytime'))
OR COUNT(DISTINCT `goodfor_when`.`name`) = 1 
ORDER BY `t`.`name`, `t`.`id`;

还有更多，除非t.id是聚合列，否则您必须这样做SELECT t.id，GROUP BY t.id如果您愿意的话ORDER BY t.id