我有一个格式化的mac地址,0018103AB839我想显示如下:00:18:10:3A:B8:39
我试图这样做,string.Format但我真的找不到确切的语法.
现在我正在尝试这样的事情:
string macaddress = 0018103AB839;
string newformat = string.Format("{0:00:00:00:00:00:00}", macaddress);
Run Code Online (Sandbox Code Playgroud)
这甚至可能吗?或者我应该使用string.Insert?
Mar*_*arc 11
重新格式化字符串以将其显示为MAC地址:
var macadres = "0018103AB839";
var regex = "(.{2})(.{2})(.{2})(.{2})(.{2})(.{2})";
var replace = "$1:$2:$3:$4:$5:$6";
var newformat = Regex.Replace(macadres, regex, replace);
// newformat = "00:18:10:3A:B8:39"
Run Code Online (Sandbox Code Playgroud)
如果要验证输入字符串,请使用此正则表达式(感谢J0HN):
var regex = String.Concat(Enumerable.Repeat("([a-fA-F0-9]{2})", 6));
Run Code Online (Sandbox Code Playgroud)
string input = "0018103AB839";
var output = string.Join(":", Enumerable.Range(0, 6)
.Select(i => input.Substring(i * 2, 2)));
Run Code Online (Sandbox Code Playgroud)
假设我们将 Mac 地址存储在一个 long 中。这是如何在格式化字符串中使用它:
ulong lMacAddr = 0x0018103AB839L;
string strMacAddr = String.Format("{0:X2}:{1:X2}:{2:X2}:{3:X2}:{4:X2}:{5:X2}",
(lMacAddr >> (8 * 5)) & 0xff,
(lMacAddr >> (8 * 4)) & 0xff,
(lMacAddr >> (8 * 3)) & 0xff,
(lMacAddr >> (8 * 2)) & 0xff,
(lMacAddr >> (8 * 1)) & 0xff,
(lMacAddr >> (8 * 0)) & 0xff);
Run Code Online (Sandbox Code Playgroud)