Mips:计算两个输入的总和

Question

看起来很简单,但我认为我的程序不会编译,因为我覆盖了$ v0寄存器？提前致谢

更新:没关系得到它,当我打印系统调用打印总和时我的订单错了...修复以防万一需要参考.

.data
prompt1: .asciiz "\n\n Enter the first integer please:"
prompt2: .asciiz "Enter the second integer please:"
result: .asciiz "The result is:"

.text

main:

    #t0-to hold first integer
    #t1-to hold second integer
    #t2- used to hold the sum of t$1 and t$2

        #first number

    li $v0, 4 #syscall to print string
        la $a0, prompt1  #address of string to print
        syscall

        li $v0, 5 #syscall to read an integer
        syscall
        move $t0, $v0  #move the number to read into $t0

    #second number
    li $v0, 4
    la $a0, prompt2
    syscall

    li $v0,5        
        syscall
    move $t1,$v0

        add $t2, $t1, $t0 #compute the sum

    #print out sum of $t2
    li $v0, 4       # load syscall print int into $v0
    move $a0, $t2   #move the number to print into $a0
    li, $v0,1
    la, $a0, result
    syscall


Done:

    li $v0, 10    #syscall to exit
        syscall

Answer 1

.data
prompt1: .asciiz "\n\n Enter the first integer please:"
prompt2: .asciiz "Enter the second integer please:"
result: .asciiz "The result is:"

              .text
main:
    #t0-to hold first integer
    #t1-to hold second integer
    #t2- used to hold the sum of t$1 and t$2
        #first number
        li $v0, 4 #syscall to print string
        la $a0, prompt1  #address of string to print
        syscall
#
        li $v0, 5 #syscall to read an integer
        syscall
        move $t0, $v0  #move the number to read into $t0
    #second number
    li $v0, 4
    la $a0, prompt2
    syscall
#
    li $v0,5        
    syscall
    move $t1,$v0
#
    #print out sum of $t2
    li $v0, 4
    la $a0, result
    syscall
#
    add $a0, $t1, $t0 #compute the sum
    li $v0, 1
    syscall
#
    li $v0, 10
    syscall