好吧,我现在已经在几个项目中使用了Hibernate,但在使用之前我没有学习它的复杂性.我开始查看使用JPA Annotations并与Spring集成的代码,一切运行良好.但是现在我想向我的学生讲授基本的Hibernate,并且我正在创建一个示例并使用文档教程第1章,我遇到了在一个持久化类中保存一组集合值的问题.
这是持久性阶级......
public class Student {
private Long id;
private String firstName;
private String lastName;
private Set<Course> courses = new HashSet<Course>();
private Set<String> contactDetails = new HashSet<String>();
//getters and setters
}
Run Code Online (Sandbox Code Playgroud)
映射文件......
<hibernate-mapping package="com.phoenixone.school.model">
<class name="Student" table="student">
<id name="id" column="studentId">
<generator class="native" />
</id>
<property name="firstName" />
<property name="lastName" />
<set name="courses" table="student_course" lazy="false">
<key column="studentId" />
<many-to-many column="courseId" class="Course" />
</set>
<set name="contactDetails" table="contactDetails">
<key column="studentId" />
<element type="string" column="contactDetail" />
</set>
</class>
</hibernate-mapping>
Run Code Online (Sandbox Code Playgroud)
DAO(保存部分)
public class StudentDaoHibernate {
public void save(Student student){
Session session = HibernateUtil.getSessionFactory().getCurrentSession();
session.beginTransaction();
session.save(student);
session.getTransaction().commit();
}
}
Run Code Online (Sandbox Code Playgroud)
测试部分......
public class TestStudentDaoHibernate {
public static void main(String[] args) {
CourseDaoHibernate courseDao = new CourseDaoHibernate();
Course c1 = new Course();
c1.setCourseCode("CWD");
c1.setCourseName("Web Dev");
courseDao.save(c1);
Set<Course> courses = new HashSet<Course>();
courses.add(c1);
Student student = new Student();
student.setFirstName("Bob");
student.setLastName("Santos");
student.setCourses(courses);
student.getContactDetails().add("123456789");
StudentDaoHibernate dao = new StudentDaoHibernate();
dao.save(student);
}
}
Run Code Online (Sandbox Code Playgroud)
当我执行这些代码行时......
Session session = HibernateUtil.getSessionFactory().getCurrentSession()
session.beginTransaction();
Student student = (Student)session.createCriteria(Student.class)
.add(Restrictions.eq("id", new Long(1))).uniqueResult();
System.out.println("First Name: " + student.getFirstName());
System.out.println("Last Name: " + student.getLastName());
System.out.println("Courses enrolled with...");
for(Course c:student.getCourses()){
System.out.println(c.getCourseName());
}
System.out.println("Contact details...");
for(String s:student.getContactDetails()){
System.out.println(s);
}
Run Code Online (Sandbox Code Playgroud)
我得到的是这个......
名字:Bob
姓:Santos
课程注册...
Web Dev
联系方式...
这导致我得出字符串"123456789"未保存的结论.您认为我的代码有什么问题?谢谢!
| 归档时间: |
|
| 查看次数: |
11197 次 |
| 最近记录: |