Fil*_*lip 5 java date jodatime
我想要2个月之间的java.util.Date月数,而不计算月份的日期.所以我只想比较年份和月份.
monthsBetween(new Date(2012,01,28), new Date(2012,02,01)) ---> 1
monthsBetween(new Date(2012,02,27), new Date(2012,02,28)) ---> 0
monthsBetween(new Date(2012,03,28), new Date(2012,07,01)) ---> 4
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我试过这个(返回0,预期1),使用Joda-time:
private static int monthsBetween(final Date fromDate, final Date toDate) {
DateTime date1 = new DateTime().withDate(2012, 1, 20);
DateTime date2 = new DateTime().withDate(2012, 2, 13);
PeriodType monthDay = PeriodType.yearDayTime().withDaysRemoved();
Period difference = new Period(date1, date2, monthDay);
int months = difference.getMonths();
return months;
}
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而且这个(相同的结果),使用Joda-time:
private static int monthsBetween(final Date fromDate, final Date toDate) {
return Months.monthsBetween(new DateTime(fromDate), new DateTime(toDate).getMonths();
}
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我怎么能做到这一点?
你要求整月的数量 - 这与说"忽略月份部分"不同.
首先,我建议使用LocalDate而不是DateTime计算.理想情况下,根本不要使用java.util.Date,并从输入LocalDate开始(例如,通过直接解析文本或数据来自哪里.)在两个日期中将月中的日期设置为1,然后取差几个月:
private static int monthsBetweenIgnoreDays(LocalDate start, LocalDate end) {
start = start.withDayOfMonth(1);
end = end.withDayOfMonth(1);
return Months.monthsBetween(start, end).getMonths();
}
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此版本基于JDK Calendar:
public static void main(String[] args) throws Exception {
SimpleDateFormat f = new SimpleDateFormat("yyyy-MM-dd");
Date d1 = f.parse("2012-01-01");
Date d2 = f.parse("2012-02-02");
int n = differenceInMonths(d1, d2);
System.out.println(n);
}
private static int differenceInMonths(Date d1, Date d2) {
Calendar c1 = Calendar.getInstance();
c1.setTime(d1);
Calendar c2 = Calendar.getInstance();
c2.setTime(d2);
int diff = 0;
if (c2.after(c1)) {
while (c2.after(c1)) {
c1.add(Calendar.MONTH, 1);
if (c2.after(c1)) {
diff++;
}
}
} else if (c2.before(c1)) {
while (c2.before(c1)) {
c1.add(Calendar.MONTH, -1);
if (c1.before(c2)) {
diff--;
}
}
}
return diff;
}
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