按组添加ID列

jon*_*ats 19 validation r unique

我想基于两列纬度和经度在R中创建唯一ID,以便重复的位置具有相同的群集ID.

例如:

LAT        LONG    Cluster_ID
13.5330 -15.4180   1
13.5330 -15.4180   1
13.5330 -15.4180   1
13.5330 -15.4180   1
13.5330 -15.4170   2
13.5330 -15.4170   2
13.5330 -15.4170   2
13.5340 -14.9350   3
13.5340 -14.9350   3
13.5340 -15.9170   4
13.3670 -14.6190   5
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Mat*_*rde 25

这是使用的一种方式interaction.

d <- read.table(text='LAT LONG
13.5330 -15.4180 
13.5330 -15.4180 
13.5330 -15.4180 
13.5330 -15.4180 
13.5330 -15.4170 
13.5330 -15.4170 
13.5330 -15.4170 
13.5340 -14.9350 
13.5340 -14.9350 
13.5340 -15.9170 
13.3670 -14.6190', header=TRUE)

d <- transform(d, Cluster_ID = as.numeric(interaction(LAT, LONG, drop=TRUE)))

#       LAT    LONG Cluster_ID
# 1  13.533 -15.418          2
# 2  13.533 -15.418          2
# 3  13.533 -15.418          2
# 4  13.533 -15.418          2
# 5  13.533 -15.417          3
# 6  13.533 -15.417          3
# 7  13.533 -15.417          3
# 8  13.534 -14.935          4
# 9  13.534 -14.935          4
# 10 13.534 -15.917          1
# 11 13.367 -14.619          5
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编辑:合并@ Spacedman的建议供应drop=TRUEinteraction.

  • 在你的`interaction`调用中添加`drop = TRUE`将为你提供1到5的数字,而不是你在这里的随机代码. (2认同)

Sve*_*ein 12

数据:

dat <- read.table(text="
LAT        LONG
13.5330 -15.4180
13.5330 -15.4180
13.5330 -15.4180
13.5330 -15.4180
13.5330 -15.4170
13.5330 -15.4170
13.5330 -15.4170
13.5340 -14.9350
13.5340 -14.9350
13.5340 -15.9170
13.3670 -14.6190", header = TRUE)
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这些命令创建一个以下开头的id变量1:

comb <- with(dat, paste(LAT, LONG))
within(dat, Cluster_ID <- match(comb, unique(comb)))
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输出:

      LAT    LONG Cluster_ID
1  13.533 -15.418          1
2  13.533 -15.418          1
3  13.533 -15.418          1
4  13.533 -15.418          1
5  13.533 -15.417          2
6  13.533 -15.417          2
7  13.533 -15.417          2
8  13.534 -14.935          3
9  13.534 -14.935          3
10 13.534 -15.917          4
11 13.367 -14.619          5
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A5C*_*2T1 12

.GRP添加到data.table1.8.3,允许您执行以下操作:

# Your data, as a data.frame
dat <- read.table(text='LAT LONG
13.5330 -15.4180 
13.5330 -15.4180 
13.5330 -15.4180 
13.5330 -15.4180 
13.5330 -15.4170 
13.5330 -15.4170 
13.5330 -15.4170 
13.5340 -14.9350 
13.5340 -14.9350 
13.5340 -15.9170 
13.3670 -14.6190', header=TRUE)

# Convert it to a data.table
# with keys as the combination of LAT and LONG
library(data.table)
DT <- data.table(dat, key="LAT,LONG")
DT[, Cluster_ID:=.GRP, by=key(DT)]
DT
#        LAT    LONG Cluster_ID
#  1: 13.367 -14.619          1
#  2: 13.533 -15.418          2
#  3: 13.533 -15.418          2
#  4: 13.533 -15.418          2
#  5: 13.533 -15.418          2
#  6: 13.533 -15.417          3
#  7: 13.533 -15.417          3
#  8: 13.533 -15.417          3
#  9: 13.534 -15.917          4
# 10: 13.534 -14.935          5
# 11: 13.534 -14.935          5
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