try catch如何最终阻止工作？

Question

在C#,尝试捕获最终如何阻止工作？

所以如果有异常,我知道它将跳转到catch块然后跳转到finally块.

但是,如果没有错误,catch块将不会运行,但finally块是否会运行呢？

Answer 1

是的,无论是否存在异常,finally块都会运行.

Try
    [ tryStatements ]
    [ Exit Try ]
[ Catch [ exception [ As type ] ] [ When expression ]
    [ catchStatements ]
    [ Exit Try ] ]
[ Catch ... ]
[ Finally
    [ finallyStatements ] ] --RUN ALWAYS
End Try

请参阅:http://msdn.microsoft.com/en-us/library/fk6t46tz%28v=vs.80%29.aspx

Answer 2

该finally块始终会在方法返回之前执行。

尝试运行下面的代码，您会注意到语句Console.WriteLine("executed")中的 of在有机会返回finally之前执行。RunTry()

static void Main(string[] args)
{
    Console.WriteLine("Hello World!");
    Console.WriteLine(RunTry());
    Console.ReadLine();
}
public static int RunTry()
{
    try
    {
        throw new Exception();
    }
    catch (Exception)
    {
        return 0;
    }
    finally
    {
        Console.WriteLine("executed");
    }
    Console.WriteLine("will not be executed since the method already returned");
}

查看结果：

Hello World!
executed
0

Answer 3

是的,如果没有异常,则finally子句会被执行.举个例子

     try
        {
            int a = 10;
            int b = 20;
            int z = a + b;
        }
        catch (Exception e)
        {
            Console.WriteLine(e.Message);
        }
        finally
        {
            Console.WriteLine("Executed");
        }

所以这里如果假设发生异常也会终止执行.