我使用 Xpath 时命名空间和 libxml 的问题

Sly*_*y33 5 xpath libxml2

当我在 XPath 中使用 libxml 时遇到问题。我想解析一个 youtube 播放列表:

<?xml version='1.0' encoding='UTF-8'?>
<feed xmlns='http://www.w3.org/2005/Atom'
  xmlns:openSearch='http://a9.com/-/spec/opensearch/1.1/'
  xmlns:media='http://search.yahoo.com/mrss/'
  xmlns:batch='http://schemas.google.com/gdata/batch'
  xmlns:yt='http://gdata.youtube.com/schemas/2007'
  xmlns:gd='http://schemas.google.com/g/2005'
  gd:etag='W/&quot;Dk8DRn47eCp7ImA9WxRQGEk.&quot;'>
  <id>tag:youtube,2008:user:andyland74:playlists</id>
  <updated>2008-07-21T16:43:25.232Z</updated>
  <category scheme='http://schemas.google.com/g/2005#kind'
    term='http://gdata.youtube.com/schemas/2007#playlistLink'/>
  <title>Playlists of andyland74</title>
  <logo>http://www.youtube.com/img/pic_youtubelogo_123x63.gif</logo>
  <link rel='related' type='application/atom+xml'
    href='http://gdata.youtube.com/feeds/api/users/andyland74?v=2'/>
  <link rel='alternate' type='text/html'
    href='http://www.youtube.com/profile_play_list?user=andyland74'/>
  <link rel='http://schemas.google.com/g/2005#feed'
    type='application/atom+xml'
    href='http://gdata.youtube.com/feeds/api/users/andyland74/playlists?v=2'/>
  <link rel='http://schemas.google.com/g/2005#post'
    type='application/atom+xml'
    href='http://gdata.youtube.com/feeds/api/users/andyland74/playlists?v=2'/>
  <link rel='http://schemas.google.com/g/2005#batch'
    type='application/atom+xml'
    href='http://gdata.youtube.com/feeds/api/users/andyland74/playlists/batch?v=2'/>
  <link rel='self' type='application/atom+xml'
    href='http://gdata.youtube.com/feeds/api/users/andyland74/playlists?...'/>
  <link rel='service' type='application/atomsvc+xml'
    href='http://gdata.youtube.com/feeds/api/users/andyland74/playlists?alt=...'/>
  <author>
    <name>andyland74</name>
    <uri>http://gdata.youtube.com/feeds/api/users/andyland74</uri>
  </author>
  <generator version='2.0'
    uri='http://gdata.youtube.com/'>YouTube data API</generator>
  <openSearch:totalResults>3</openSearch:totalResults>
  <openSearch:startIndex>1</openSearch:startIndex>
  <openSearch:itemsPerPage>25</openSearch:itemsPerPage>
  <entry gd:etag='W/&quot;Dk8DRn47eCp7ImA9WxRQGEk.&quot;'>
    <id>tag:youtube,2008:user:andyland74:playlist:8BCDD04DE8F771B2</id>
    <published>2007-11-04T17:30:27.000-08:00</published>
    <updated>2008-07-15T12:33:20.000-07:00</updated>
    <app:edited xmlns:app='http://www.w3.org/2007/app'>2008-07-15T12:33:20.000-07:00</app:edited>
    <category scheme='http://schemas.google.com/g/2005#kind'
      term='http://gdata.youtube.com/schemas/2007#playlistLink'/>
    <title>My New Playlist Title</title>
    <summary>My new playlist Description</summary>
    <content type='application/atom+xml;type=feed'
      src='http://gdata.youtube.com/feeds/api/playlists/8BCDD04DE8F771B2?v=2'/>
    <link rel='related' type='application/atom+xml'
      href='http://gdata.youtube.com/feeds/api/users/andyland74?v=2'/>
    <link rel='alternate' type='text/html'
      href='http://www.youtube.com/view_play_list?p=8BCDD04DE8F771B2'/>
    <link rel='self' type='application/atom+xml'
      href='http://gdata.youtube.com/feeds/api/users/andyland74/playlists/8BCDD04DE8F771B2?v=2'/>
    <link rel='edit' type='application/atom+xml'
      href='http://gdata.youtube.com/feeds/api/users/andyland74/playlists/8BCDD04DE8F771B2?v=2'/>
    <author>
      <name>andyland74</name>
      <uri>http://gdata.youtube.com/feeds/api/users/andyland74</uri>
    </author>
    <yt:countHint>9</yt:countHint>
  </entry>
</feed>
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当我使用以下 xpath 表达式“/feed”时,xmlXPathEvalExpression 说我没有找到。

如果我删除 feed 的所有 xmlns 属性,它就可以工作。即使使用 xmlns 属性,我怎样才能使它工作?

我将 libxml 与 Objective-C 一起使用

eas*_*sel 2

您没有发布查询代码,但听起来您没有使用 XpathContext 注册名称空间。这是xmlXPathRegisterNS的 API 文档,我相信它会满足您的需求。它不允许您注册默认名称空间,因此您需要将 XPath 表达式更改为 /feed:feed 等。

  • 对于 xmlXpathRegisterNS 函数来说没问题。但为什么我无法注册默认命名空间?如果我只想获取 &lt;feed&gt; ,为什么要使用 /feed:feed 表达式? (2认同)