在KDE Python应用程序中处理KeyboardInterrupt？

Question

我正在研究PyKDE4/PyQt4应用程序,Autokey,我注意到当我发送程序一个CTRL + C时,键盘中断在我与应用程序交互之前不会被处理.单击菜单项或更改复选框.

lfaraone@stone:~$ /usr/bin/autokey
^C^C^C
Traceback (most recent call last):
  File "/usr/lib/python2.6/dist-packages/autokey/ui/popupmenu.py", line 113, in on_triggered
    def on_triggered(self):
KeyboardInterrupt
^C^C^C
Traceback (most recent call last):
  File "/usr/lib/python2.6/dist-packages/autokey/ui/configwindow.py", line 423, in mousePressEvent
    def mousePressEvent(self, event):
KeyboardInterrupt

尽管在/ usr/bin/autokey中有以下内容:

#!/usr/bin/python
# -*- coding: utf-8 -*-

import sys
from autokey.autokey import Application

a = Application()
try:
    a.main()
except KeyboardInterrupt:
    a.shutdown()
sys.exit(0)

为什么没有捕获KeyboardInterrupt:

• 当我发出它时,而不是当我接下来在GUI中执行操作时
• 通过最初的try/except子句？

使用Python 2.6运行Ubuntu 9.04.

Answer 1

试着这样做:

import signal
signal.signal(signal.SIGINT, signal.SIG_DFL)

在调用之前a.main().

更新:请记住,Ctrl-C可用于GUI应用程序中的复制.最好在Qt中使用Ctrl + \,这将导致事件循环终止并关闭应用程序.