将Guid表示为一组整数

Question

如果我想将guid表示为一组整数,我将如何处理转换？我正在考虑获取guid的字节数组表示并将其分解为最少可能转换回原始guid的32位整数.代码示例首选...

此外,结果整数数组的长度是多少？

Answer 1

  System.Guid guid = System.Guid.NewGuid();
    byte[] guidArray = guid.ToByteArray();

    // condition
    System.Diagnostics.Debug.Assert(guidArray.Length % sizeof(int) == 0);

    int[] intArray = new int[guidArray.Length / sizeof(int)];

    System.Buffer.BlockCopy(guidArray, 0, intArray, 0, guidArray.Length);


    byte[] guidOutArray = new byte[guidArray.Length];

    System.Buffer.BlockCopy(intArray, 0, guidOutArray, 0, guidOutArray.Length);

    System.Guid guidOut = new System.Guid(guidOutArray);

    // check
    System.Diagnostics.Debug.Assert(guidOut == guid);

Answer 2

由于GUID只有16个字节,因此可以将其转换为四个整数:

Guid id = Guid.NewGuid();

byte[] bytes = id.ToByteArray();
int[] ints = new int[4];
for (int i = 0; i < 4; i++) {
   ints[i] = BitConverter.ToInt32(bytes, i * 4);
}

转换回来只是将整数作为字节数组并放在一起:

byte[] bytes = new byte[16];
for (int i = 0; i < 4; i++) {
   Array.Copy(BitConverter.GetBytes(ints[i]), 0, bytes, i * 4, 4);
}
Guid id = new Guid(bytes);