use*_*019 6 html php xpath domdocument
我想将一个网页转换成leet(1337)与XPath和PHP对话.
它只能用PHP完成,但HTML节点也可以用leet speak替换.
示例($ html是网页):
$find = array("a","b","c","d","e","f","g","h","i","j"."k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z");
$repl = array("4","b","c","d","3","f","g","h","1","j","k","1","m","n","0","p","9","r","5","7","u","v","w","x","y","2");
$html = str_replace($find, $repl, $html);
这也取代了HTML节点.
可以使用XPath选择器text()使用XPath和PHP来完成吗？示例($ html是网页):
$dom = new DOMDocument();
$dom->loadHTML($html);
$xpath = new DOMXPath($dom);
$xpath->query('//text()');
\\HERE THE REPLACING IN XPATH
尝试这个：
$dom = new DOMDocument;
$dom->loadHTML( $html );
$xpath = new DOMXPath( $dom );
$nodes = $xpath->query( '//text()' );
foreach( $nodes as $node )
{
$node->nodeValue = str_replace( $find, $repl, $node->nodeValue );
}
echo $dom->saveHTML();
请注意，这可能是满足您需求的更有用的 xpath 查询：
$nodes = $xpath->query( '//head/title/text() | //body//text()' );
...因为这只会替换 中的文本<head><title>或<body>. 可能不想替换可能的样式、Javascript 等等。;-)
旁注：我已经用您的查找和替换字符数组对此进行了测试，但是它们有一些可疑之处，我无法弄清楚。替换字符似乎并不总是与找到的字符对齐。我不知道为什么会这样。
我已经重新创建了数组，这些对我有用：
$find = array('a','b','c','d','e','f','g','h','i','j'.'k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z');
$repl = array('4','b','c','d','3','f','g','h','1','j'.'k','1','m','n','0','p','9','r','5','7','u','v','w','x','y','2');
我只是不明白为什么你的数组不适合我。:-/ 也许是编码问题？如果有人想插话并冒险猜测，请这样做。
编辑：正如 rxdazn 注意到的那样，"j"."k"问题出在第一个数组中，我完全忽略了它，正如您从我重新创建的数组中看到的那样（我将 $find 复制到 $repl，替换了引号，并填写了 leet 字符）。