awk删除重复的字段和计数

Question

我有一个问题,我试图解决使用只有awk.

我在结构中有一个csv文件:

Easting  Northing    Latitude    Longitude   Locality Name

Easting  "Northing"  "Latitude"  "Longitude"     "LocalityName"
364208  176288           51.48441   -2.51685     "Fishponds"
358596  172813           51.45278   -2.59726     "Bristol City Centre"
358886  177828           51.49789   -2.59367     "Southmead"
358839  177839           51.49798   -2.59435     "Southmead"
358980  177882           51.49838   -2.59232     "Southmead"
359009  177863           51.49821   -2.5919          "Southmead"
358839  177529           51.4952        -2.59431     "Southmead"
359475  168262           51.41192   -2.58409     "Hengrove Park"
358945  173526           51.45921   -2.59232     "Bristol"
358943  173525           51.4592    -2.59235     "Bristol"
358941  173524           51.45919   -2.59238     "Bristol"
358940  173523           51.45919   -2.59239     "Bristol"
358945  173528           51.45923   -2.59232     "Bristol"
358936  173520           51.45916   -2.59245     "Bristol"
358936  173521           51.45917   -2.59245     "Bristol"
358932  173516           51.45912   -2.5925          "Bristol"

等...我正在尝试编写一个awk脚本,它将计算每个Locality名称的实例和打印打印这样一个输出将是:

Fishponds 1
Bristol City Centre 1
Southmead 5
Hengrove park 1
Bristol 8

到目前为止,我有这个:

BEGIN { i = 0; state = 0; names[NR]; FS=","; }

{
#for each element in names array, check if already exists.
    for(j=0;j<=i;j++)
    {
        if(names[j] == $5)
        {
        state = 1;
        break;
        }
    }
# If the name doesnt already exist add to names array
    if(state == 0)
    {
        names[i] = $5;
        i++;
    }
    state = 0;
}

END { 
    for(x=0;x<=i;x++)
    {
    print names[x];
    }
}

有希望对位置进行排序并删除重复项,但我仍然想不出一个好方法来计算每个位置的实例然后将它们列回.

Answer 1

更简单的洗液:

awk -F '"' 'NR>3 {locname[$2]++}
            END { for (n in locname) {print n, locname[n] } }' INPUTFILE

首先将输入文件分隔符设置为",因此第二个字段将是位置名称.跳过第一行(标题).利用数组(键是第二个字段)来计算出现次数.在最后一行之后打印数组的键和值.