如何为一行c#代码设置超时

Question

可能重复:
将超时设置为操作

如何在c#中为一行代码设置超时.例如 RunThisLine(SomeMethod(Some Input), TimeSpan.FromSeconds(10)) ,SomeMethod以10秒的时间运行.提前致谢.

Answer 1

您可以使用任务并行库.更确切地说,您可以使用 Task.Wait(TimeSpan):

using System.Threading.Tasks;

var task = Task.Run(() => SomeMethod(input));
if (task.Wait(TimeSpan.FromSeconds(10)))
    return task.Result;
else
    throw new Exception("Timed out");

Answer 2

您可以使用IAsyncResult和Action类/接口来实现此目的.

public void TimeoutExample()
{
    IAsyncResult result;
    Action action = () =>
    {
        // Your code here
    };

    result = action.BeginInvoke(null, null);

    if (result.AsyncWaitHandle.WaitOne(10000))
         Console.WriteLine("Method successful.");
    else
         Console.WriteLine("Method timed out.");
}

Answer 3

我使用这样的东西(你应该添加代码来处理各种失败):

    var response = RunTaskWithTimeout<ReturnType>(
        (Func<ReturnType>)delegate { return SomeMethod(someInput); }, 30);


    /// <summary>
    /// Generic method to run a task on a background thread with a specific timeout, if the task fails,
    /// notifies a user
    /// </summary>
    /// <typeparam name="T">Return type of function</typeparam>
    /// <param name="TaskAction">Function delegate for task to perform</param>
    /// <param name="TimeoutSeconds">Time to allow before task times out</param>
    /// <returns></returns>
    private T RunTaskWithTimeout<T>(Func<T> TaskAction, int TimeoutSeconds)
    {
        Task<T> backgroundTask;

        try
        {
            backgroundTask = Task.Factory.StartNew(TaskAction);
            backgroundTask.Wait(new TimeSpan(0, 0, TimeoutSeconds));
        }
        catch (AggregateException ex)
        {
            // task failed
            var failMessage = ex.Flatten().InnerException.Message);
            return default(T);
        }
        catch (Exception ex)
        {
            // task failed
            var failMessage = ex.Message;
            return default(T);
        }

        if (!backgroundTask.IsCompleted)
        {
            // task timed out
            return default(T);
        }

        // task succeeded
        return backgroundTask.Result;
    }