Rok*_*okG 0 python iteration hex
假设我有以下ascii十六进制字符串"4a65737573".我现在如何迭代它,包装固定数量的字符,但总是递增2.即4a65,6573,7375 ......
ins*_*get 10
这应该这样做:
In [218]: mystr = "4a65737573"
In [219]: for i in range(0, len(mystr), 2):
.....: print mystr[i:i+4]
.....:
4a65
6573
7375
7573
73