如何在代码中编写JSON字符串值？

Question

我想将以下字符串存储在String变量中

{ "ID": "123", "DateOfRegistration": "2012-10-21T00:00:00 + 05:30", "状态":0}

这是我使用的代码..

String str="{"Id":"123","DateOfRegistration":"2012-10-21T00:00:00+05:30","Status":0}";

..但它显示错误..

Answer 1

你必须这样做

String str="{\"Id\":\"123\",\"DateOfRegistration\":\"2012-10-21T00:00:00+05:30\",\"Status\":0}";

请参阅此参考
也来自msdn :)

Short Notation  UTF-16 character    Description
\'  \u0027  allow to enter a ' in a character literal, e.g. '\''
\"  \u0022  allow to enter a " in a string literal, e.g. "this is the double quote (\") character"
\\  \u005c  allow to enter a \ character in a character or string literal, e.g. '\\' or "this is the backslash (\\) character"
\0  \u0000  allow to enter the character with code 0
\a  \u0007  alarm (usually the HW beep)
\b  \u0008  back-space
\f  \u000c  form-feed (next page)
\n  \u000a  line-feed (next line)
\r  \u000d  carriage-return (move to the beginning of the line)
\t  \u0009  (horizontal-) tab
\v  \u000b  vertical-tab

Answer 2

使用 Verbatim String Literals ( @"...")，您可以通过将双引号与双引号对交换来编写内联多行 json - "" 而不是 "。示例：

string str = @"
{
    ""Id"": ""123"",
    ""DateOfRegistration"": ""2012-10-21T00:00:00+05:30"",
    ""Status"": 0
}";

Answer 3

我更喜欢这个,只要确保你的字符串中没有单引号

string str = "{'Id':'123','DateOfRegistration':'2012 - 10 - 21T00: 00:00 + 05:30','Status':0}".Replace("'", "\"");

Answer 4

微调@sudhAnsu63 回答这是一个单行：

使用NET 核心

string str = JsonSerializer.Serialize(
  new {    
    Id = 2,
    DateOfRegistration = "2012-10-21T00:00:00+05:30",
    Status = 0
  }
);

与Json.Net

string str = JsonConvert.SerializeObject(
  new {    
    Id = 2,
    DateOfRegistration = "2012-10-21T00:00:00+05:30",
    Status = 0
  }
);

有没有必要实例化dynamic ExpandoObject。

Answer 5

C# 11 引入了一项名为原始字符串文字的新功能。它使得使用 JSON 变得非常容易。只需使用三个双引号字符 ( """) 作为标记而不是使用一个双引号字符 ( ) 将字符串括起来：

string str = """{"Id":"123","DateOfRegistration":"2012-10-21T00:00:00+05:30","Status":0}""";

Nick Chapsas 的相关 YouTube 视频：C# 11 中的字符串变得更好了。

Answer 6

还有一种替代方法，可以使用Expando对象或XElement编写这些复杂的JSON，然后进行序列化。

https://blogs.msdn.microsoft.com/csharpfaq/2009/09/30/dynamic-in-c-4-0-introducing-the-expandoobject/

dynamic contact = new ExpandoObject();

contact.Name = “Patrick Hines”;

contact.Phone = “206-555-0144”;

contact.Address = new ExpandoObject();

contact.Address.Street = “123 Main St”;

contact.Address.City = “Mercer Island”;

contact.Address.State = “WA”;

contact.Address.Postal = “68402”;

//Serialize to get Json string using NewtonSoft.JSON
string Json = JsonConvert.SerializeObject(contact);

Answer 7

您必须这样对字符串中的引号进行转义：

String str="{\"Id\":\"123\",\"DateOfRegistration\":\"2012-10-21T00:00:00+05:30\",\"Status\":0}";