php html下拉到mysql

Question

好的,我在最后一天左右一直在试验php和我的sql.

但我一直试图创建一个简单的输入表单,用户将在网页上填写然后它流入我的(mysql)服务器到目前为止,我已经采取了FirstName LastName性别和城市但是下一个问题是状态和那个提出一个问题,我有50个州的下拉,但我认为我的html缺少一个因素巫婆将允许我的PHP脚本抓住它

这是我的州下拉列表的代码

State: <select>
<option value="Alabama">Alabama</option>
<option value="Alaska">Alaska</option>
<option value="Arizona">Arizona</option>
<option value="Arkansas">Arkansas</option>
<option value="California">California</option>
<option value="Colorado">Colorado</option>
<option value="Connecticut">Connecticut</option>
<option value="Delaware">Delaware</option>
<option value="Florida">Florida</option>
<option value="Georgia">Georgia</option>
<option value="Hawaii">Hawaii</option>
<option value="Idaho">Idaho</option>
<option value="Illinois">Illinois</option>
<option value="Indiana">Indiana</option>
<option value="Iowa">Iowa</option>
<option value="Kansas">Kansas</option>
<option value="Kentucky">Kentucky</option>
<option value="Louisiana">Louisiana</option>
<option value="Maine">Maine</option>
<option value="Maryland">Maryland</option>
<option value="Massachusetts">Massachusetts</option>
<option value="Michigan">Michigan</option>
<option value="Mississippi">Mississippi</option>
<option value="Missouri">Missouri</option>
<option value="Montana">Montana</option>
<option value="Nebraska">Nebraska</option>
<option value="Nevada">Nevada</option>
<option value="New Hampshire">New Hampshire</option>
<option value="New Jersey">New Jersey</option>
<option value="New Mexico">New Mexico</option>
<option value="New York">New York</option>
<option value="North Carolina">North Carolina</option>
<option value="North Dakota">North Dakota</option>
<option value="Ohio">Ohio</option>
<option value="Oklahoma">Oklahoma</option>
<option value="Oregon">Oregon</option>
<option value="Pennsylvania">Pennsylvania</option>
<option value="Rhode Island">Rhode Island</option>
<option value="South Carolina">South Carolina</option>
<option value="South Dakota">South Dakota</option>
<option value="Tennessee">Tennessee</option>
<option value="Texas">Texas</option>
<option value="Utah">Utah</option>
<option value="Vermont">Vermont</option>
<option value="Virginia">Virginia</option>
<option value="Washington">Washington</option>
<option value="West Virginia">West Virginia</option>
<option value="Wisconsin">Wisconsin</option>
<option value="Wyoming">Wyoming</option>
</select><br>

这就是我如何选择其他元素

<?php
include"config.php";
$FirstName = $_POST['FirstName'];
$LastName = $_POST['LastName'];
$Gender = $_POST['Gender'];

$insert = 'INSERT into content(FirstName, LastName, Gender)     VALUES("'.$FirstName.'","'.$LastName.'", "'.$Gender.'")';
mysql_query($insert);

不知道怎么做？

Answer 1

首先,您<select>需要一个名称属性:

<select name="state">

然后你需要在你的PHP中捕获它:

$state = $_POST['state'];

然后你需要将它添加到你的sql语句中

$insert = 'INSERT into content(FirstName, LastName, Gender, State)     VALUES("'.$FirstName.'","'.$LastName.'", "'.$Gender.'", "'.$state.'")';

这假设您的content表中有一个名为state 的列,它在性别之后直接驻留.

并且一如既往不使用mysql_*函数.使用mysqli或PDO.