我在Delphi中使用弹出菜单.我希望以"无线电组"的方式使用它,如果用户选择了一个项目,则检查它并且不检查其他项目.我尝试使用AutoCheck属性,但这允许检查多个项目.有没有办法设置弹出菜单,以便只能检查一个项目?
Zar*_*tog 12
要处理弹出(或任何其他)菜单项(如无线电组项目),请为要在无线电组中拥有的每个项目将"RadioItem"属性设置为true.
它不会显示复选标记,而是显示所选项目的项目符号,但它将按照您想要的方式工作,并且视觉提示实际上将匹配Windows标准.
Zartog是正确的,但是如果要保留复选框,请将此事件分配给弹出菜单中的每个项目.
请注意,此代码有点毛茸茸,因为它不依赖于知道弹出菜单的名称(因此,使用"GetParentComponent"查找).
procedure TForm2.OnPopupItemClick(Sender: TObject);
var
i : integer;
begin
with (Sender as TMenuItem) do begin
//if they just checked something...
if Checked then begin
//go through the list and *un* check everything *else*
for i := 0 to (GetParentComponent as TPopupMenu).Items.Count - 1 do begin
if i <> MenuIndex then begin //don't uncheck the one they just clicked!
(GetParentComponent as TPopupMenu).Items[i].Checked := False;
end; //if not the one they just clicked
end; //for each item in the popup
end; //if we checked something
end; //with
end;
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您可以在运行时将事件分配给表单上的每个弹出框(如果您想这样做):
procedure TForm2.FormCreate(Sender: TObject);
var
i,j: integer;
begin
inherited;
//look for any popup menus, and assign our custom checkbox handler to them
if Sender is TForm then begin
with (Sender as TForm) do begin
for i := 0 to ComponentCount - 1 do begin
if (Components[i] is TPopupMenu) then begin
for j := 0 to (Components[i] as TPopupMenu).Items.Count - 1 do begin
(Components[i] as TPopupMenu).Items[j].OnClick := OnPopupItemClick;
end; //for every item in the popup list we found
end; //if we found a popup list
end; //for every component on the form
end; //with the form
end; //if we are looking at a form
end;
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回答此答案下方的评论:如果您要求至少检查一个项目,请使用此项目代替第一个代码块.您可能希望在oncreate事件中设置默认选中的项目.
procedure TForm2.OnPopupItemClick(Sender: TObject);
var
i : integer;
begin
with (Sender as TMenuItem) do begin
//go through the list and make sure *only* the clicked item is checked
for i := 0 to (GetParentComponent as TPopupMenu).Items.Count - 1 do begin
(GetParentComponent as TPopupMenu).Items[i].Checked := (i = MenuIndex);
end; //for each item in the popup
end; //with
end;
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