Dan*_*Dan 4 javascript ajax json
在我用AJAX发送它之前,我有什么特别要对JSON对象做的吗?我的代码看起来像这样:
runAjax(JSON.stringify(data));
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}
function runAjax(JSONstring)
{
ajax = getHTTPObject();
var params = "?data=" + JSONstring;
ajax.open("POST", "createtrip.php", true);
ajax.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
ajax.setRequestHeader("Content-length", params.length);
ajax.setRequestHeader("Connection", "close");
ajax.onreadystatechange = serverSpeaks;
ajax.send(params);
}
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现在服务器没有收到数据.我在服务器端获取null,但客户端JSONString已设置.有什么我做错了吗?
您通过POST发送数据,您不需要变量'?'开头的字符params,我还建议您对 JSONString进行编码以避免出现问题.
请注意,您缺少变量的var语句ajax,这是全局声明它(window.ajax),我认为您不需要全局...
function runAjax(JSONstring) {
var params = "data=" + encodeURIComponent(JSONstring),
ajax = getHTTPObject();
ajax.open("POST", "createtrip.php", true);
ajax.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
ajax.setRequestHeader("Content-length", params.length);
ajax.setRequestHeader("Connection", "close");
ajax.onreadystatechange = serverSpeaks;
ajax.send(params);
}
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