Django:'str'对象没有属性'user'

Question

这是我的视图代码:

@login_required
def get_top(type):
    o = Work.objects.filter(types = "Fan Fiction").order_by("-date_updated")[:10]
    list = []
    for o in o:
        l.title = o.title
        l.href = "/" + o.id
        list.append(l)
    return l

@login_required
def main_home(request):
    fanfiction = get_top("ff")
    poetry = get_top("pw")
    originalwork = get_top("ow")
    return render_to_response("Main/main_home.html", {'STATIC_URL':STATIC_URL, "poetry":poetry, "fan":fanfiction, "original":originalwork})

这是模型的代码:

class Work(models.Model):
    title = models.CharField(max_length=30)
    summery = models.TextField()
    user = models.ForeignKey(User)
    date_published = models.DateField()
    date_updated = models.DateField()
    one_shot = models.BooleanField()
    completed = models.BooleanField()
    TYPES = (
        ('FF', 'Fan Fiction'),
        ('OF', 'Original Work'),
        ('PW', 'Poetry Work'),
        )
    types = models.CharField(max_length=2, choices=TYPES)
    fandom1 = models.ForeignKey(Book, blank = True, null= True, related_name='f_1')
    fandom2 = models.ForeignKey(Book, blank = True, null= True, related_name='f_2')
    def __unicode__(self):
    return self.title + '-' + self.user.email

这是错误:'str' object has no attribute 'user'在"get_top("ff")"

Answer 1

请删除@login_required装饰器的get_top方法.

这样做的目的是@login_required尝试验证该用户是否已登录.这是试图找到一个User对象实例中ff这是str因此堆栈跟踪.通常从obj @login_required获取,但因为你没有传递它因此错误.Userrequestget_top

我的建议是你应该维护一些方法,views.py这些方法与其中urls.py一些可能需要的API网址相关联@login_required.其他方法集是辅助方法(如get_top).这些不会暴露在外面的世界(因此没有必要@login_required).

如果您必须get_top在内部和外部公开,那么您的第一个参数get_top必须是request对象,然后是其他参数.