Hibernate + oracle序列+触发器

Question

我有一个表,其索引由一个使用序列的触发器自动填充(Oracle数据库)

CREATE TABLE A
(
  IDS                           NUMBER(10)      NOT NULL
)


CREATE OR REPLACE TRIGGER A_TRG
BEFORE INSERT
ON A REFERENCING NEW AS New OLD AS Old
FOR EACH ROW
BEGIN
  :new.IDS := A_SEQ.nextval;
END A_TRG;
/

我有一个匹配的Java类:

Class A {
   @Id
   @SequenceGenerator(name = "aSequence", sequenceName = "A_SEQ", allocationSize = 1)
   @GeneratedValue(generator = "aSequence", strategy = GenerationType.SEQUENCE)
   @Column(name = "IDS")
   Long id;

   ...
}

当我尝试像这样坚持A的实例时:

EntityTransaction transaction = entityManager.getTransaction();
transaction.begin();
A a = new A();
Long id = getHibernateTemplate().save(a);
transaction.commit();

我遇到这个问题:

• save call = "X"返回的代码中的ID

• 数据库中的ID = "X + 1"

有没有办法设置Hibernate让数据库触发器创建ID？

谢谢

Answer 1

使用Oracle Trigger在HIbernate问题中找到响应,用于从序列生成id

我需要调整我的触发器才能在没有给出ID的情况下运行:

CREATE OR REPLACE TRIGGER A_TRG
BEFORE INSERT
ON A REFERENCING NEW AS New OLD AS Old
FOR EACH ROW
WHEN (New.IDS is null) -- (1)
BEGIN
  :new.IDS := A_SEQ.nextval;
END A_TRG;
/

(1)这一行允许Hibernate手动调用A_SEQ.nextVal来设置ID,然后绕过触发器,否则Hibernate将无用地获取nextval,因为触发器将始终重置ID再次调用nextval