ANSI C - 初始化数组

Question

我一直在做的是:

int arr[] = {2, 3, 4};

它总是有效的.

我听说过使用指针初始化新数组的更好方法:

int *arr = {2, 3, 4};

但是,它在任何IDE中都不起作用,它会抛出一些错误int differs in levels of indirection from int,或者too many initializers.我该怎么做？

Answer 1

int arr[] = {2, 3, 4};

很好,完全正确.无需改变.

Answer 2

初始化似乎对我有用,在gcc上,但不正确.

int *arr = {2, 3, 4}; //weird behaviour, stores first value `2` as read-only

int arr[] = {2, 3, 4}; //array decl

前者不是初始化数组的正确方法.

对于char*,它更有意义

char* arr = "abcde"; //Pointer to a read-only char array in memory

char[] arr = "abcde"; //Normal char array

区别:

前者写入程序集的Rodata(常量,只读数据)部分,而后者则驻留在读/写数据段中.任何改变前者的尝试都可能导致分段错误.

存储值的位置不同.

char* arr = "abcde";
arr[1] = 'f'; //(undefined behavior)

char[] arr2 = "abcde";
arr2[1] = 'f'; //no issue