我想使用自定义对话框进行引脚验证.这是我的代码:
public void fetchUI()
{
add=(Button)findViewById(R.id.pinButton);
add.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
// TODO Auto-generated method stub
final AlertDialog.Builder alert = new AlertDialog.Builder(MainActivity.this);
final EditText input = new EditText(MainActivity.this);
input.setTransformationMethod(PasswordTransformationMethod.getInstance());
alert.setView(input);
alert.setTitle("Type Your PIN");
alert.setIcon(R.drawable.ic_launcher);
alert.setMessage("Please Type Your PIN below to Authenticate");
alert.setPositiveButton("Ok", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
}
});
alert.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
dialog.cancel();
}
});
alert.show();
}
});
}
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现在我想这样做:如果我用正确的PIN点击OK,那么对话框就会消失.否则,如果我点击OK,它就不会消失.我怎样才能做到这一点?任何帮助将不胜感激.
final String CORRECT_PIN = "123123"; // Should come from somewhere else than a local variable
alert.setPositiveButton("Ok", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
if (CORRECT_PIN.equals(input.getText().toString()) {
dialog.dismiss();
} else {
input.setError(getString(R.string.error_incorrect_pin));
}
}
});
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编辑:上面的代码提供了处理验证的正确方法.但是,为了防止在单击按钮后取消对话框,您需要在自定义对话框按钮中包含自己的按钮.
其他可能性:仅在引脚正确时启用"确定"按钮.您需要在EditText和onTextChange方法中添加文本更改侦听器,请执行以下操作:
input.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
alert.getButton(AlertDialog.BUTTON_POSITIVE).setEnabled(CORRECT_PIN.equals(input.getText().toString());
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void afterTextChanged(Editable s) {
}
});
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