PL/SQL-更新员工薪资,加薪金额错误

Kat*_*ine 2 sql database plsql updating

我需要更新部门 40 和 70 员工的工资。部门 40 的所有员工都会加薪 10%,而部门 70 的员工都会加薪 15%。

我有 1 名来自 70 部门的员工,他的工资是 10000,所以他会有 15% 的加薪。我预计他的工资会变成11500,结果却变成了13225。我不明白为什么。40 部门的员工加薪是正确的,只有 70 部门的这个员工加薪是错误的。

这是 pl/sql 块..

SET serveroutput ON
DECLARE

  CURSOR cur_emp
  IS
    SELECT * FROM employees WHERE department_id = 40 OR department_id = 70;
  rec_emp cur_emp%rowtype;
BEGIN
  OPEN cur_emp;
  LOOP
    FETCH cur_emp INTO rec_emp;
    IF rec_emp.department_id = 40 THEN
      UPDATE employees
      SET salary                = salary + (salary * 0.1)
      WHERE employee_id         = rec_emp.employee_id;
    elsif rec_emp.department_id = 70 THEN
      UPDATE employees
      SET salary        = salary + (salary * 0.15)
      WHERE employee_id = rec_emp.employee_id;
    END IF;
    EXIT
  WHEN cur_emp%notfound;
  END LOOP;
  CLOSE cur_emp;
END;
/
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谁能帮我解决这个问题吗?谢谢

小智 5

不需要存储过程:

update employees
   set salary = case 
                  when department_id = 40 then salary * 1.10
                  when department_id = 70 then salary * 1.15
                  else salary -- not strictly necessary. just to make sure.
                end
where department_id in (40,70);
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如果您坚持以慢速方式(PL/SQL 中的循环)执行此操作,则使用 anUPDATE ... WHERE CURRENT OF可能会比“不相关”更新更快。

您的代码的真正问题是您“太晚”离开循环。即使游标在获取后没有返回任何内容,您仍然会执行更新。您应该将 放在IF 子句和更新EXIT WHEN ... 之前。

DECLARE

  CURSOR cur_emp
  IS
    SELECT * FROM employees WHERE department_id = 40 OR department_id = 70;
  rec_emp cur_emp%rowtype;
BEGIN
  OPEN cur_emp;
  LOOP
    FETCH cur_emp INTO rec_emp;

    EXIT WHEN cur_emp%notfound; -- **** leave the loop right here, BEFORE doing the update *****

    IF rec_emp.department_id = 40 THEN
      UPDATE employees
      SET salary                = salary + (salary * 0.1)
      WHERE employee_id         = rec_emp.employee_id;
    elsif rec_emp.department_id = 70 THEN
      UPDATE employees
      SET salary        = salary + (salary * 0.15)
      WHERE employee_id = rec_emp.employee_id;
    END IF;

  END LOOP;
  CLOSE cur_emp;
END;
/
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更有效的方法是使用可更新游标:

DECLARE

  CURSOR cur_emp
  IS
    SELECT department_id, salary 
    FROM employees 
    WHERE department_id in (40,70)
    FOR UPDATE OF salary;

  rec_emp cur_emp%rowtype;
  new_sal number(12,2);
BEGIN
  OPEN cur_emp;
  LOOP
    FETCH cur_emp INTO rec_emp;

    EXIT WHEN cur_emp%NOTFOUND;

    IF rec_emp.department_id = 40 THEN
      new_sal := rec_emp.salary * 1.10;
    elsif rec_emp.department_id = 70 THEN
      new_sal := rec_emp.salary * 1.15;
    END IF;

    UPDATE employees
       SET salary  = new_sal
    WHERE CURRENT OF cur_emp;

  END LOOP;
  CLOSE cur_emp;
END;
/
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实际上,使用会更清楚地揭示错误,因为如果您将 放在更新之后,WHERE CURRENT OF循环将失败并显示。invalid rowidexit