枚举当前visual studio项目中的所有文件

bra*_*ing 2 c# visual-studio-extensions visual-studio-2012

我正在尝试编写一个简单的Visual Studio 2012扩展.我已经生成了扩展模板,可以从工具菜单中弹出一个对话框.

我想枚举当前打开的项目中的所有文件,然后根据一些规则过滤它们.我正在寻找的是一个返回IEnumerable的代码片段.FileHandle应该具有以下接口或类似的东西.

interface IFileHandle {
        // Return the string 
        string Path;
        // Open the file in the editor
        void OpenEditorFor();
}
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仅供参考我正在尝试为视觉工作室构建模糊文件查找器.当前文件搜索不太合适,因为您必须具有完全匹配.我可以处理编写索引器和模糊搜索器,但Visual Studio扩展编写的界面目前有点神秘.

bra*_*ing 9

这似乎是一个简单的答案.在visual studio扩展的上下文中将返回所有文件.

public IEnumerable<ProjectItem> Recurse(ProjectItems i)
{
    if (i!=null)
    {
        foreach (ProjectItem j in i)
        {
            foreach (ProjectItem k in Recurse(j))
            {
                yield return k;
            }
        }

    }
}
public IEnumerable<ProjectItem> Recurse(ProjectItem i)
{
    yield return i;
    foreach (ProjectItem j in Recurse(i.ProjectItems ))
    {
        yield return j;
    }
}

public IEnumerable<ProjectItem> SolutionFiles()
{
    Solution2 soln = (Solution2)_applicationObject.Solution;
    foreach (Project project in soln.Projects)
    {
        foreach (ProjectItem item in Recurse(project.ProjectItems))
        {
            yield return item;
        }
    }
}
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然后你就可以用它做一些巧妙的技巧,比如在我的CommandT克隆核心实现搜索功能.

private static string Pattern(string src)
{
    return ".*" + String.Join(".*", src.ToCharArray());
}

private static bool RMatch(string src, string dest)
{
    try
    {
        return Regex.Match(dest, Pattern(src), RegexOptions.IgnoreCase).Success;
    }
    catch (Exception e)
    {
        return false;
    }
}

private static List<string> RSearch(
string word,
IEnumerable<string> wordList,
double fuzzyness)
{
    // Tests have prove that the !LINQ-variant is about 3 times
    // faster!
    List<string> foundWords =
        (
            from s in wordList
            where RMatch(word, s) == true
            orderby s.Length ascending 
            select s
        ).ToList();

    return foundWords;
}
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用的像

var list = RSearch("bnd", SolutionFiles().Select(x=>x.Name))
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