Android - 在Canvas中绘制位图

Question

我目前有一个5 x 5平方的迷宫游戏(占用屏幕宽度并均匀分割).然后,对于使用x和y坐标的每个框,我使用drawRect来绘制彩色背景.

我遇到的问题是我现在需要在同一位置绘制图像,因此替换当前的普通背景颜色填充.

这是我目前用于drawRect的代码(一些例子):

// these are all the variation of drawRect that I use
canvas.drawRect(x, y, (x + totalCellWidth), (y + totalCellHeight), green);
canvas.drawRect(x + 1, y, (x + totalCellWidth), (y + totalCellHeight), green);
canvas.drawRect(x, y + 1, (x + totalCellWidth), (y + totalCellHeight), green);

然后我还需要为画布中的所有其他方块实现背景图像.此背景将在其顶部绘制简单的1px黑色线条,当前代码以灰色背景绘制.

background = new Paint();
background.setColor(bgColor);
canvas.drawRect(0, 0, width, height, background);

如果可能的话,请你指点一下.如果是这样,那么我可以做的最好的方法是什么,同时尽量减少内存使用量并使1个图像扩展和缩小以填充相关的方形空间(这会因所有不同的屏幕尺寸而变化,因为它会分裂整体屏幕宽度均匀).

Answer 1

使用该Canvas方法public void drawBitmap (Bitmap bitmap, Rect src, RectF dst, Paint paint).设置dst为您想要缩放整个图像的矩形的大小.

编辑:

这是在画布上绘制正方形中位图的可能实现.假设位图是二维数组(例如Bitmap bitmapArray[][];),并且画布是方形的,因此方形位图宽高比不会失真.

private static final int NUMBER_OF_VERTICAL_SQUARES = 5;
private static final int NUMBER_OF_HORIZONTAL_SQUARES = 5;

...

    int canvasWidth = canvas.getWidth();
    int canvasHeight = canvas.getHeight();

    int squareWidth = canvasWidth / NUMBER_OF_HORIZONTAL_SQUARES;
    int squareHeight = canvasHeight / NUMBER_OF_VERTICAL_SQUARES;
    Rect destinationRect = new Rect();

    int xOffset;
    int yOffset;

    // Set the destination rectangle size
    destinationRect.set(0, 0, squareWidth, squareHeight);

    for (int horizontalPosition = 0; horizontalPosition < NUMBER_OF_HORIZONTAL_SQUARES; horizontalPosition++){

        xOffset = horizontalPosition * squareWidth;

        for (int verticalPosition = 0; verticalPosition < NUMBER_OF_VERTICAL_SQUARES; verticalPosition++){

            yOffset = verticalPosition * squareHeight;

            // Set the destination rectangle offset for the canvas origin
            destinationRect.offsetTo(xOffset, yOffset);

            // Draw the bitmap into the destination rectangle on the canvas
            canvas.drawBitmap(bitmapArray[horizontalPosition][verticalPosition], null, destinationRect, null);
        }
    }