luajit2.0.0 - 分段错误:11

Question

我使用http://lua-users.org/wiki/SimpleLuaApiExample中的一个简单示例进行测试.该示例可以与libluajit.a静态链接并成功,但运行时会出现此错误消息:

Segmentation fault: 11

我使用的是2012-11-08发布的LuaJIT-2.0.0.我的操作系统是Mac OSX Lion 10.7.5.

$ uname -a
Darwin macmatoMacBook-Pro.local 11.4.2 Darwin Kernel Version 11.4.2: Thu Aug 23 16:25:48 PDT 2012; root:xnu-1699.32.7~1/RELEASE_X86_64 x86_64

测试步骤:

编译luajit-2.0.0

$ cd lj2
$ ls
COPYRIGHT Makefile  README    doc       dynasm    etc       src
$ make
==== Building LuaJIT 2.0.0 ====
make -C src
DYNLINK   libluajit.so
LINK      luajit
OK        Successfully built LuaJIT
==== Successfully built LuaJIT 2.0.0 ====
$ rm src/*.so            # force to use the static version: libluajit.a
$ cd ..

编译并运行示例应用程序

无论test.c的和script.lua来自这里.文件夹lj2包含上面luajit-2.0.0的源代码,刚编译成功.

$ ls
lj2 script.lua test.c 

使用clang编译器

$ clang -o test test.c -I./lj2/src -L./lj2/src -lluajit
$ ./test
Segmentation fault: 11

使用gcc编译器

$ gcc -o test test.c -I./lj2/src -L./lj2/src -lluajit
$ ./test 
Segmentation fault: 11

---

但是如果我用test.c替换lj2/src/luajit.c,它会给我一个成功.这很奇怪.见下文:

$ cd lj2
$ make clean
$ mv src/luajit.c src/luajit.c.orig 
$ cp ../test.c src/luajit.c
$ make
$ cp src/luajit ../
$ cd ..
$ ./luajit
The table the script received has:
1   2
2   4
3   6
4   8
5   10
Returning data back to C
Script returned: 30  

Answer 1

问题解决了.有一节介绍如何在此页面中嵌入LuaJIT:http://luajit.org/install.html

• 如果您在OSX上构建一个直接或间接链接到> LuaJIT的64位应用程序,则需要将主可执行文件与这些标志链接:

  -pagezero_size 10000 -image_base 100000000

此外,建议重新定义在OSX/x64上运行时加载的所有(自编译)共享库(例如Lua的C扩展模块).见:man rebase

现在,让我再次测试一下:

$ clang -o test test.c -O3 -I./lj2/src -L./lj2/src -lluajit -pagezero_size 10000 -image_base 100000000
$ ./test 
The table the script received has:
1   2
2   4
3   6
4   8
5   10
Returning data back to C
Script returned: 30

而valgrind回归

$ valgrind ./test
bad executable (__PAGEZERO is not 4 GB)
valgrind: ./test: cannot execute binary file

那是另一个问题.