以干净的方式查看变量内容

Question

所以我用来查看变量内容的方法是在我的模板工具包中使用Data :: Dumper:

[% USE Dumper %]
[% Dumper.dump(varname) %]

但是我得到的结果有点乱 - 关于表关系,列类型和attrbitues等的所有信息.

我想知道是否有一种方法可以获得一个"干净"的变量内容 - 因为只有来自查询的当前结果+相关的结果集(即当我使用带有cakephp框架的php时,有一个'debug(varname)'命令提供了这样的结果,看起来像这样http://pastebin.com/Hut0LnAb).

Answer 1

数据::打印机救援!它的对象转储更易于人类阅读:

my $obj = SomeClass->new;
p($obj);
# produces:
\ SomeClass  {
    Parents       Moose::Object
    Linear @ISA   SomeClass, Moose::Object
    public methods (3) : bar, foo, meta
    private methods (0)
    internals: {
       _something => 42,
    }
}

它与Template Toolkit兼容:

[% USE DataPrinter %]
html-formatted, colored dump of the same data structure:
[% DataPrinter.dump_html( myvar ) %]

它"知道"如何处理DBIx :: Class:

use Data::Printer
    filters => {
        -external => [qw[DB]], # use DB filter
    }, class => {
        expand => 2, # traverse object 2-levels deep
        linear_isa => 0, # hide not-so-relevant information
    };

...

my $obj = $schema
    ->resultset('AddressState')
    ->search({}, { prefetch => [qw[country]] })
    ->single;
p $obj;