南非身份证号码验证并获得年龄和性别

Question

我研究了这个,但我使用的代码似乎都没有用.南非身份证号码包含出生日期和性别.我想要的只是当它们的ID号被输入到输入字段时输入该信息并验证它,最好是在jQuery或javascript中

任何帮助表示赞赏,

的Dawid

Answer 1

您可以使用Koenyn的正则表达式验证,不确定输入中的一位数字(0-9？)如何代表性别,但基于您提供的此工具和David Russell 使用Javascript验证南非ID号,这里是未经测试的尝试:

更新1: 关注此主题后,南非的身份证号码是由什么组成的？,我更新了我的实施,包括性别和公民身份测试.

更新2: 忘记id_month + 1在日期字符串中包装月份数增量fullDate,使用Dawid修正更新解决方案.

HTML标记:

<div id="error"></div>

<form id="idCheck">
    <p>Enter the ID Number: <input id="idnumber" /> </p>
    <p> <input type="submit" value="Check" /> </p>
</form>

<div id="result"> </div>

Javascript:

function Validate() {
    // first clear any left over error messages
    $('#error p').remove();

    // store the error div, to save typing
    var error = $('#error');

    var idNumber = $('#idnumber').val();


    // assume everything is correct and if it later turns out not to be, just set this to false
    var correct = true;

    //Ref: http://www.sadev.co.za/content/what-south-african-id-number-made
    // SA ID Number have to be 13 digits, so check the length
    if (idNumber.length != 13 || !isNumber(idNumber)) {
        error.append('<p>ID number does not appear to be authentic - input not a valid number</p>');
        correct = false;
    }

    // get first 6 digits as a valid date
    var tempDate = new Date(idNumber.substring(0, 2), idNumber.substring(2, 4) - 1, idNumber.substring(4, 6));

    var id_date = tempDate.getDate();
    var id_month = tempDate.getMonth();
    var id_year = tempDate.getFullYear();

    var fullDate = id_date + "-" + (id_month + 1) + "-" + id_year;

    if (!((tempDate.getYear() == idNumber.substring(0, 2)) && (id_month == idNumber.substring(2, 4) - 1) && (id_date == idNumber.substring(4, 6)))) {
        error.append('<p>ID number does not appear to be authentic - date part not valid</p>');
        correct = false;
    }

    // get the gender
    var genderCode = idNumber.substring(6, 10);
    var gender = parseInt(genderCode) < 5000 ? "Female" : "Male";

    // get country ID for citzenship
    var citzenship = parseInt(idNumber.substring(10, 11)) == 0 ? "Yes" : "No";

    // apply Luhn formula for check-digits
    var tempTotal = 0;
    var checkSum = 0;
    var multiplier = 1;
    for (var i = 0; i < 13; ++i) {
        tempTotal = parseInt(idNumber.charAt(i)) * multiplier;
        if (tempTotal > 9) {
            tempTotal = parseInt(tempTotal.toString().charAt(0)) + parseInt(tempTotal.toString().charAt(1));
        }
        checkSum = checkSum + tempTotal;
        multiplier = (multiplier % 2 == 0) ? 1 : 2;
    }
    if ((checkSum % 10) != 0) {
        error.append('<p>ID number does not appear to be authentic - check digit is not valid</p>');
        correct = false;
    };


    // if no error found, hide the error message
    if (correct) {
        error.css('display', 'none');

        // clear the result div
        $('#result').empty();
        // and put together a result message
        $('#result').append('<p>South African ID Number:   ' + idNumber + '</p><p>Birth Date:   ' + fullDate + '</p><p>Gender:  ' + gender + '</p><p>SA Citizen:  ' + citzenship + '</p>');
    }
    // otherwise, show the error
    else {
        error.css('display', 'block');
    }

    return false;
}

function isNumber(n) {
    return !isNaN(parseFloat(n)) && isFinite(n);
}

$('#idCheck').submit(Validate);

演示:http://jsfiddle.net/chridam/VSKNx/

Answer 2

这是我们公司的验证正则表达式:

string IdExpression = @"(?<Year>[0-9][0-9])(?<Month>([0][1-9])|([1][0-2]))(?<Day>([0-2][0-9])|([3][0-1]))(?<Gender>[0-9])(?<Series>[0-9]{3})(?<Citizenship>[0-9])(?<Uniform>[0-9])(?<Control>[0-9])";

至于使用正则表达式,它真的很简单 http://www.w3schools.com/jsref/jsref_obj_regexp.asp