如何在sqlite django ORM中实现having子句

Question

我编写了django sqlite orm语法来检索特定的记录集:

from django.db.models.aggregates import Count

JobStatus.objects.filter(
    status='PRF'
).values_list(
    'job', flat=True
).order_by(
    'job'
).aggregate(
    Count(status)__gt=3
).distinct()

但是它给了我一个错误,这个语法的sql等效对我来说很好.

这是我的sql等价物.

SELECT *
  FROM tracker_jobstatus
 WHERE status = 'PRF'
 GROUP BY job_id
HAVING COUNT(status) > 3;

我得到的结果如下

+----+--------+--------+---------+---------------------+---------+
| id | job_id | status | comment | date_and_time       | user_id |
+----+--------+--------+---------+---------------------+---------+
| 13 |      3 | PRF    |         | 2012-11-12 13:16:00 |       1 |
| 31 |      4 | PRF    |         | 2012-11-12 13:48:00 |       1 |
+----+--------+--------+---------+---------------------+---------+

我无法找到与此相关的django sqlite.

如果有人能提供帮助,我将非常感激.

Answer 1

最后我设法弄明白了.ORM语法是这样的.

from django.db.models.aggregates import Count

JobStatus.objects.filter(
    status='PRF'
).values_list(
    'job', flat=True
).order_by(
    'job'
).annotate(
    count_status=Count('status')
).filter(
    count_status__gt=1
).distinct()

Answer 2

更通用的规则:您需要创建新列(by annotate),然后筛选新列.此查询集将转换为HAVING关键字.