字节到人类可读,然后回来.没有数据丢失

Question

我需要将包含内存使用量的字符串1048576(例如:(1M))转换为人类可读的版本,反之亦然.

注意:我已经看过这里了: 可重用的库,以获得文件大小的人类可读版本？

在这里(即使它不是python): 如何将人类可读的内存大小转换为字节？

到目前为止没有什么能帮助我,所以我在其他地方看了

我在这里找到了一些可以解决此问题的内容:http://code.google.com/p/pyftpdlib/source/browse/trunk/test/bench.py​​？specpec = swn984&r = 984#137,或者,对于较短的网址:http://goo.gl/zeJZl

代码:

def bytes2human(n, format="%(value)i%(symbol)s"):
    """
    >>> bytes2human(10000)
    '9K'
    >>> bytes2human(100001221)
    '95M'
    """
    symbols = ('B', 'K', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y')
    prefix = {}
    for i, s in enumerate(symbols[1:]):
        prefix[s] = 1 << (i+1)*10
    for symbol in reversed(symbols[1:]):
        if n >= prefix[symbol]:
            value = float(n) / prefix[symbol]
            return format % locals()
    return format % dict(symbol=symbols[0], value=n)

还有一个转换功能(相同的网站):

def human2bytes(s):
    """
    >>> human2bytes('1M')
    1048576
    >>> human2bytes('1G')
    1073741824
    """
    symbols = ('B', 'K', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y')
    letter = s[-1:].strip().upper()
    num = s[:-1]
    assert num.isdigit() and letter in symbols
    num = float(num)
    prefix = {symbols[0]:1}
    for i, s in enumerate(symbols[1:]):
        prefix[s] = 1 << (i+1)*10
    return int(num * prefix[letter])

这很好,但它有一些信息丢失,例如:

>>> bytes2human(10000)
'9K'
>>> human2bytes('9K')
9216

为了解决这个问题,我改变了函数的格式 bytes2human

成: format="%(value).3f%(symbol)s")

哪个更好,给我这些结果:

>>> bytes2human(10000)
'9.766K'

但是当我尝试用human2bytes函数将它们转换回来时:

>>> human2bytes('9.766K')

Traceback (most recent call last):
  File "<pyshell#366>", line 1, in <module>
    human2bytes('9.766K')
  File "<pyshell#359>", line 12, in human2bytes
    assert num.isdigit() and letter in symbols
AssertionError

这是因为 .

所以我的问题是,如何将人类可读的版本转换回字节版本,而不会丢失数据？

注意:我知道3位小数也是一点数据丢失.但是出于这个问题的目的,让我们忽略现在,我总是可以将其改为更大的东西.

Answer 1

所以事实证明答案比我想象的要简单得多 - 我提供的其中一个链接实际上导致了更详细的函数版本:

哪个能够处理我给它的任何范围.

但是谢谢你的帮助:

这里复制的代码用于后代:

## {{{ http://code.activestate.com/recipes/578019/ (r15)
#!/usr/bin/env python

"""
Bytes-to-human / human-to-bytes converter.
Based on: http://goo.gl/kTQMs
Working with Python 2.x and 3.x.

Author: Giampaolo Rodola' <g.rodola [AT] gmail [DOT] com>
License: MIT
"""

# see: http://goo.gl/kTQMs
SYMBOLS = {
    'customary'     : ('B', 'K', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y'),
    'customary_ext' : ('byte', 'kilo', 'mega', 'giga', 'tera', 'peta', 'exa',
                       'zetta', 'iotta'),
    'iec'           : ('Bi', 'Ki', 'Mi', 'Gi', 'Ti', 'Pi', 'Ei', 'Zi', 'Yi'),
    'iec_ext'       : ('byte', 'kibi', 'mebi', 'gibi', 'tebi', 'pebi', 'exbi',
                       'zebi', 'yobi'),
}

def bytes2human(n, format='%(value).1f %(symbol)s', symbols='customary'):
    """
    Convert n bytes into a human readable string based on format.
    symbols can be either "customary", "customary_ext", "iec" or "iec_ext",
    see: http://goo.gl/kTQMs

      >>> bytes2human(0)
      '0.0 B'
      >>> bytes2human(0.9)
      '0.0 B'
      >>> bytes2human(1)
      '1.0 B'
      >>> bytes2human(1.9)
      '1.0 B'
      >>> bytes2human(1024)
      '1.0 K'
      >>> bytes2human(1048576)
      '1.0 M'
      >>> bytes2human(1099511627776127398123789121)
      '909.5 Y'

      >>> bytes2human(9856, symbols="customary")
      '9.6 K'
      >>> bytes2human(9856, symbols="customary_ext")
      '9.6 kilo'
      >>> bytes2human(9856, symbols="iec")
      '9.6 Ki'
      >>> bytes2human(9856, symbols="iec_ext")
      '9.6 kibi'

      >>> bytes2human(10000, "%(value).1f %(symbol)s/sec")
      '9.8 K/sec'

      >>> # precision can be adjusted by playing with %f operator
      >>> bytes2human(10000, format="%(value).5f %(symbol)s")
      '9.76562 K'
    """
    n = int(n)
    if n < 0:
        raise ValueError("n < 0")
    symbols = SYMBOLS[symbols]
    prefix = {}
    for i, s in enumerate(symbols[1:]):
        prefix[s] = 1 << (i+1)*10
    for symbol in reversed(symbols[1:]):
        if n >= prefix[symbol]:
            value = float(n) / prefix[symbol]
            return format % locals()
    return format % dict(symbol=symbols[0], value=n)

def human2bytes(s):
    """
    Attempts to guess the string format based on default symbols
    set and return the corresponding bytes as an integer.
    When unable to recognize the format ValueError is raised.

      >>> human2bytes('0 B')
      0
      >>> human2bytes('1 K')
      1024
      >>> human2bytes('1 M')
      1048576
      >>> human2bytes('1 Gi')
      1073741824
      >>> human2bytes('1 tera')
      1099511627776

      >>> human2bytes('0.5kilo')
      512
      >>> human2bytes('0.1  byte')
      0
      >>> human2bytes('1 k')  # k is an alias for K
      1024
      >>> human2bytes('12 foo')
      Traceback (most recent call last):
          ...
      ValueError: can't interpret '12 foo'
    """
    init = s
    num = ""
    while s and s[0:1].isdigit() or s[0:1] == '.':
        num += s[0]
        s = s[1:]
    num = float(num)
    letter = s.strip()
    for name, sset in SYMBOLS.items():
        if letter in sset:
            break
    else:
        if letter == 'k':
            # treat 'k' as an alias for 'K' as per: http://goo.gl/kTQMs
            sset = SYMBOLS['customary']
            letter = letter.upper()
        else:
            raise ValueError("can't interpret %r" % init)
    prefix = {sset[0]:1}
    for i, s in enumerate(sset[1:]):
        prefix[s] = 1 << (i+1)*10
    return int(num * prefix[letter])


if __name__ == "__main__":
    import doctest
    doctest.testmod()
## end of http://code.activestate.com/recipes/578019/ }}}