如何修复C++编译器错误"无法将'Type'转换为'const Type*'"？

Question

这是完整的错误消息:

错误:无法将'MyTime'转换为'const MyTime*'以将参数'1'转换为'int DetermineElapsedTime(const MyTime*,const MyTime*)'|

这是我的代码:

#include <iostream>
#include<cstdlib>
#include<cstring>

using namespace std;
struct MyTime { int hours, minutes, seconds; };
int DetermineElapsedTime(const MyTime *t1, const MyTime *t2);
const int hourSeconds = 3600;
const int minSeconds = 60;

int DetermineElapsedTime(const MyTime *t1, const MyTime *t2)
{
    long timeDiff = ((((t2->hours * hourSeconds) + (t2->minutes * minSeconds) + t2->seconds) -
                   ((t1->hours * hourSeconds) + (t1->minutes * minSeconds) + t1->seconds)));
    return(timeDiff);
}


int main(void)
{
    char delim1, delim2;
    MyTime tm, tm2;
    cout << "Input two formats for the time. Separate each with a space. Ex: hr:min:sec\n";
    cin >> tm.hours >> delim1 >> tm.minutes >> delim2 >> tm.seconds;
    cin >> tm2.hours >> delim1 >> tm2.minutes >> delim2 >> tm2.seconds;

    DetermineElapsedTime(tm, tm2);

    return 0;

}

有什么办法可以解决吗？请随时指出您看到的任何其他错误.我知道修复DetermineTimeElapsed以正确输出hr:min:sec格式.但是现在我需要克服这个问题.

Answer 1

错误应该在以下行:

DetermineElapsedTime(tm, tm2);

您正在将MyTime对象传递给上述函数const MyTime*.

通过传递对象地址来修复它:

DetermineElapsedTime(&tm, &tm2);

或者更好的C++方式:通过更改函数原型来接受对象引用:

int DetermineElapsedTime(const MyTime &t1, const MyTime &t2);

身体也会相应改变; 例如->将被.操作员等替换.