sha*_*ath 2 mongodb mongodb-query
我正在尝试更新集合中子文档数组中的数组字段。我的收藏是这样的:
{
_id:"1",
employees:[{ eid:"2",
ename:"test",
is_user:true
},
{ eid:"3",
ename:"test2",
is_user:true
}
]
}
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我正在尝试更新 is_user 状态并尝试以下方式:
db.users.update({_id:"1","employees.eid":"2"},{$set:"employees.$.is_user":true},true);
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我也试过:
db.users.update({_id:"1","employees.$.eid":"2"},{$set:"employees.$.is_user":true},true);
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但是当我运行查找时,对于查询:
db.users.find({_id:"1","employees.eid":"2"});
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它仍然给我什么。有人可以帮我吗?谢谢..
那确实有效。
> db.test.insert({_id:"1", employees:[{ eid:"2", ename:"test", is_user:true }, { eid:"3", ename:"test2", is_user:true } ] })
> db.test.find({_id:"1","employees.eid":"2"});
{ "_id" : "1", "employees" : [ { "eid" : "2", "ename" : "test", "is_user" : true }, { "eid" : "3", "ename" : "test2", "is_user" : true } ] }
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对于$您想要使用它的操作员,例如:
> db.test.insert({_id:"1", employees:[{ eid:"2", ename:"test", is_user:false }, { eid:"3", ename:"test2", is_user:false } ] })
> db.test.find({_id:"1", "employees.eid":"2", "employees.is_user": true});
> db.test.update({_id:"1", "employees.eid":"2"}, {$set: {"employees.$.is_user": true}});
> db.test.find({_id:"1", "employees.eid":"2", "employees.is_user": true});
{ "_id" : "1", "employees" : [ { "eid" : "2", "ename" : "test", "is_user" : true }, { "eid" : "3", "ename" : "test2", "is_user" : false } ] }
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请注意在数组中的两个对象上如何将 insert ofis_user设置为 tofalse以及更新后匹配的对象从falseto更新true,这是您要查找的内容吗?
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