在编程中,我正在编写一个用户选择实体的代码,然后计算体积和表面积.但是我没有直接选择,而是向用户提供了询问有关实体的额外信息的选项,如果他们输入数字然后"显示"(例如'1 show').他们可以继续询问,直到选择一个实体,所以我使用了一个while循环.
循环不起作用.如果循环的条件无效,它仍会进入循环并且不让我离开.请帮忙.我觉得这很简单.我试图进行整数和字符串转换,没有它帮助.
#11/07/12
#A program that asks user for input and calculates SA and Volume of a chosen solid
print "Which solid would you like to calculate?"
print " "
print "1. Tetrahedron"
print "2. Dodecahedron"
print "3. Cone"
print "4. Sphere"
print "5. Icosahedron"
print ' '
print "If you want extra information on the solid, enter the solid's number and then add show. Example: 1 show"
print "If not, just enter the number"
choice = raw_input('----->')
#Where asks if user wants extra information on the solids, loops until solid is chosen
while choice != '1' or choice != '2' or choice != '3' or choice != '4' or choice != '5':
if choice == "1 show":
print "A tetrahedron is composed of four congruent triangle faces. "
if choice =='2 show':
print "A dodecahedron is a polyhedron composed of 12 pentagonal faces. "
if choice == '3 show':
print 'A cone is a geometric solid that tapers smoothly from a circular base to an apex. '
if choice == '4 show':
print "A sphere is a perfectly round circle. "
if choice == '5 show':
print 'An icosahedron is a regular polyhedron with 20 congruent equilateral triangular faces'
choice = raw_input('Your new choice: ')
if choice == 1: # Tetradedron
tetraside = raw_input("What is the length of your solid's side? ")
tetrabaseA = ((3 ** (1/2)) / 4) * tetraside**2
tetraheight = 9 * ((6 ** (1/2)) / 3) * tetraside
tetraSA = 4 * tetrabaseA
tetraV = (1 / 3) * tetrabaseA * tetraheight
Run Code Online (Sandbox Code Playgroud)
你的while病情有误.想一想:即使choice等于'1',条件choice != '2'也是如此,所以整个条件总会得到满足.
你需要类似的东西
while choice not in {'1', '2', ...}:
Run Code Online (Sandbox Code Playgroud)
要么
while choice not in set(map(str, range(1, 6))): # a fancier version
Run Code Online (Sandbox Code Playgroud)
或者只是更改所有or以and你的条件.