我在2D Java游戏中做了一种引力,我试图创建一个跳跃算法.我已经环顾四周,看不到任何有助于在波浪中上下移动的算法的帮助.
这是Game.java中的代码:
package game;
import java.awt.*;
public class Game extends GameLoop{
public void init(){
setSize(864,480);
Thread th = new Thread(this);
th.start();
offscreen = createImage(864,480);
d = offscreen.getGraphics();
addKeyListener(this);
}
public void paint(Graphics g){
d.clearRect(0, 0, 864, 480);
d.drawImage(background, 0, 0, this);
d.drawImage(person, x, y, this);
g.drawImage(offscreen, 0, 0, this);
}
public void update(Graphics g){
paint(g);
}
}
Run Code Online (Sandbox Code Playgroud)
这是GameLoop.java中的代码:
package game;
import java.applet.*;
import java.awt.*;
import java.awt.event.*;
import java.awt.image.BufferedImage;
import java.io.File;
import java.io.IOException;
import javax.imageio.*;
public class GameLoop extends Applet implements Runnable, KeyListener{
public int x, y;
public Image offscreen;
public Graphics d;
public boolean up, down, left, right;
public BufferedImage background, w1, w2, w3, w4, w5, w6, w7, w8, person, s1, s2;
public int counter, counter2;
public void run(){
x = 100;
y = 100;
try {
background = ImageIO.read(new File("background.png"));
w1 = ImageIO.read(new File("walk1.png"));
w2 = ImageIO.read(new File("walk2.png"));
w3 = ImageIO.read(new File("walk3.png"));
w4 = ImageIO.read(new File("walk4.png"));
w5 = ImageIO.read(new File("walk5.png"));
w6 = ImageIO.read(new File("walk6.png"));
w7 = ImageIO.read(new File("walk7.png"));
w8 = ImageIO.read(new File("walk8.png"));
s1 = ImageIO.read(new File("stancel.png"));
s2 = ImageIO.read(new File("stancer.png"));
} catch (IOException e1) {
e1.printStackTrace();
}
person = s1;
while(true){
x = 100;
y = 100;
while(true){
if (y <= 304 && up != true){
y+=10;
}
counter++;
counter2++;
if (counter >= 20){
counter = 0;
}
if (counter >= 0 && counter <= 5 && right == true){
person = w1;
}
if (counter > 5 && counter < 10 && right == true){
person = w2;
}
if (counter >= 10 && counter <= 15 && right == true){
person = w3;
}
if (counter > 15 && right == true){
person = w4;
}
if (counter2 >= 20){
counter2 = 0;
}
if (counter2 >= 0 && counter2 <= 5 && left == true){
person = w5;
}
if (counter2 > 5 && counter2 < 10 && left == true){
person = w6;
}
if (counter2 >= 10 && counter2 <= 15 && left == true){
person = w7;
}
if (counter2 > 15 && left == true){
person = w8;
}
if (left == true){
x-=4;
}
if (right == true){
x+=4;
}
if (up == true){
y-=4;
}
if (down == true){
y+=4;
}
if ( x <= -10 ){
x = -10;
}
if ( y <= 0 ){
y = 0;
}
if ( x >= 824 ){
x = 824;
}
if ( y >= 304 ){
y = 304;
}
repaint();
try{
Thread.sleep(20);
} catch(InterruptedException e){
e.printStackTrace();
}
}
}
}
//@Override
public void keyPressed(KeyEvent e) {
if(e.getKeyCode() == 37){
left = true;
}
if(e.getKeyCode() == 38){
up = true;
}
if(e.getKeyCode() == 39){
right = true;
}
if(e.getKeyCode() == 40){
down = true;
}
}
//@Override
public void keyReleased(KeyEvent e) {
if(e.getKeyCode() == 37){
left = false;
person = s2;
}
if(e.getKeyCode() == 38){
up = false;
}
if(e.getKeyCode() == 39){
right = false;
person = s1;
}
if(e.getKeyCode() == 40){
down = false;
}
}
//@Override
public void keyTyped(KeyEvent e) {
}
}
Run Code Online (Sandbox Code Playgroud)
我想我需要一个计数器,counter3作为一个双,但我不确定一个算法会在y轴上达到某个点,然后向下移动.任何帮助表示赞赏.
最简单的波函数之一是我们的老朋友sine:

所以对于跳跃动作,你可能会喜欢上半sine段.您可以使用java.util.Math,将一系列数字传递0给180(多少取决于您希望跳转的帧数). 例如:
Math.sin(0.0); // = 0.0
Math.sin(30.0); // = 0.5
Math.sin(60.0); // = 0.9
Math.sin(90.0); // = 1.0
Math.sin(120.0); // = 0.9
Math.sin(150.0); // = 0.5
Math.sin(180.0); // = 0.0
Run Code Online (Sandbox Code Playgroud)